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## anonymous 5 years ago 6ab^2/5a^3b divided by 12ab/15a^5b I dont know if im supposed to flip the second half and make the division into a multiplication or simplify first.

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1. anonymous

Alright, first let's cut down the question into 2 parts :):$\frac{6ab^2}{5a^3b}$ this part is divide by : $\frac{12ab}{15a^5b}$ now let's just write it down in a simpler form ^_^: $\frac{6ab^2}{5a^3b} \div \frac{12ab}{15a^5b}$ now there's a rule that says, when you divide 2 fractions or any other number, you have to flip the other fraction/number and multiply instead of divide like this: $\frac{6ab^2}{5a^3b} \times \frac{15a^5b}{12ab}$ now let's simplify :) $= \frac{3a^2b}{2}$ is it clearer now :)?

2. anonymous

thanks, so does that mean the flipping rule always comes first no matter what?

3. anonymous

yep ^_^ and np

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