an=(n-1)!/n^2,1≤n≤5

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an=(n-1)!/n^2,1≤n≤5

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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just plug in the numbers 1 thru 5 for n to get the sequence
i know but im gettin weird answers so i know im doin it wrong
ok are you doing the factorials correctly 3! = 3*2*1

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Other answers:

for example, a1= 2, a2= 24, a3=181440 now i know thats wrong
a1 = (1-1)!/1^2 a1 = 0!/1 0! = 1 a1 = 1
a2 = (2-1)!/2^2 a2 = 1!/4 1! = 1 a2 = 1/4
so a3= 2/9 ???
yes good
n a4= 3/16, and a5=4/25 ??
no thats wrong...
a4 = 3*2*1/16
so a4=6/16 ???
yes but remember to reduce
ok so a4=3/8, ans a5=24/25 ???
correct
! means multiply every number til you get to one :)
can u possibly help me with another problem? this one i dont get because it is a work problem...
ok
thank you i just posted it

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