A collection of dimes is arranged in a triangular array with 18 coins in the base row, 17 in the next, 16 in the next, and so forth with 1 dime in the last row. Find the value of the collection.
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first find num of dimes then multiply by 0.1 to get value in dollars
sequence goes 18,17,16...1
so you are subtracting 1 each time
there is a formula for sum of arithmetic sequence
sum = 1/2*n*(a1+an)
n=num of rows
im still a little lost
ok just concentrate on the formula for the sum of the series
we need a value for n, a1, and an
n is num of rows
a1 is first num in sequence
an is last num in sequence
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whats first num in sequence
how many dimes in first row?
how many dimes in last row?
ok top row has one dime
bottom row has 18 dimes
since each row has one more than prev row
there are a total of 18 rows
sum = 1/2*18*(1+18)
sum = 1/2*18*19
sum = 9*19
sum = 171
171 dimes = 17.10 in dollars