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anonymous
 5 years ago
A collection of dimes is arranged in a triangular array with 18 coins in the base row, 17 in the next, 16 in the next, and so forth with 1 dime in the last row. Find the value of the collection.
anonymous
 5 years ago
A collection of dimes is arranged in a triangular array with 18 coins in the base row, 17 in the next, 16 in the next, and so forth with 1 dime in the last row. Find the value of the collection.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0first find num of dimes then multiply by 0.1 to get value in dollars sequence goes 18,17,16...1 so you are subtracting 1 each time there is a formula for sum of arithmetic sequence sum = 1/2*n*(a1+an) n=num of rows

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im still a little lost

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok just concentrate on the formula for the sum of the series we need a value for n, a1, and an n is num of rows a1 is first num in sequence an is last num in sequence

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0whats first num in sequence

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how many dimes in first row? how many dimes in last row?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0still lost? ok top row has one dime bottom row has 18 dimes since each row has one more than prev row there are a total of 18 rows 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18 sum = 1/2*18*(1+18) sum = 1/2*18*19 sum = 9*19 sum = 171 171 dimes = 17.10 in dollars

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ah ok got it... thank you!!!
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