A collection of dimes is arranged in a triangular array with 18 coins in the base row, 17 in the next, 16 in the next, and so forth with 1 dime in the last row. Find the value of the collection.

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A collection of dimes is arranged in a triangular array with 18 coins in the base row, 17 in the next, 16 in the next, and so forth with 1 dime in the last row. Find the value of the collection.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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first find num of dimes then multiply by 0.1 to get value in dollars sequence goes 18,17,16...1 so you are subtracting 1 each time there is a formula for sum of arithmetic sequence sum = 1/2*n*(a1+an) n=num of rows
im still a little lost
ok just concentrate on the formula for the sum of the series we need a value for n, a1, and an n is num of rows a1 is first num in sequence an is last num in sequence

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Other answers:

hmmmm
whats first num in sequence
how many dimes in first row? how many dimes in last row?
still lost? ok top row has one dime bottom row has 18 dimes since each row has one more than prev row there are a total of 18 rows 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18 sum = 1/2*18*(1+18) sum = 1/2*18*19 sum = 9*19 sum = 171 171 dimes = 17.10 in dollars
ah ok got it... thank you!!!
no prob

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