## anonymous 5 years ago Find all the solutions of the Differential Equation dy/dt - 2y^2 = ty^2

1. anonymous

2. anonymous

After that take an integral.

3. anonymous

that helps, thanks.

4. anonymous

$y'[t]-2 y^2=t y^2\to y'[t]=t y^2+2 y^2$ $\int\limits y'[t] \, dt=\int\limits \left(-2 y^2+t y^2\right) \, dt$ $y[t]=-2 t y^2+\frac{t^2 y^2}{2}$