Find the sum of the finite geometric series. 3-9+27-81+243-729+2187-6561+19683-59049

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Find the sum of the finite geometric series. 3-9+27-81+243-729+2187-6561+19683-59049

Mathematics
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for the finite G series the formula is [a(1-r^(n-1)]/1-r
a=3, r=-3 , n= 10 S(n) = a(1-r^(n) ) / (1-r) sub etc lol
\[\frac {a(1-r^n) }{1-r}\]

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Other answers:

:( again mistake
yes right :)
wait min
you might be right, yeh, thought it looked a little strange I wikipedia it, and it is a(1-r^(n-1) ) / (1-r)
oh let me check
hmm no you were right before
no I was correct firsdt time
yes , just went to check a high school maths study guide lying around
yes the first 1 is right
damm wikipedia, its usually a good resource for maths
but wikipedia shows the same formula u wrote at the first place :)
I can seem to find it, ahh I am bit tired
cant*
i am lost now lol
yes its for sure :)
\[\frac {a(1-r^n)}{1-r}\] sub in a=3, r=-3, n=10
3[1-(-3)^10]/1-3 =3[1-3^10]/2
so is the answer 1536?
???
u calculated it?does it come 1536?
yes that is what i got, is that what you got?
i dint calculate :)
oh ok... but does that make sense? my answer???
sure :)
lol ok thank you

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