anonymous
  • anonymous
Find the sum of the finite geometric series. 3-9+27-81+243-729+2187-6561+19683-59049
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
for the finite G series the formula is [a(1-r^(n-1)]/1-r
anonymous
  • anonymous
a=3, r=-3 , n= 10 S(n) = a(1-r^(n) ) / (1-r) sub etc lol
anonymous
  • anonymous
\[\frac {a(1-r^n) }{1-r}\]

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anonymous
  • anonymous
:( again mistake
anonymous
  • anonymous
yes right :)
anonymous
  • anonymous
wait min
anonymous
  • anonymous
you might be right, yeh, thought it looked a little strange I wikipedia it, and it is a(1-r^(n-1) ) / (1-r)
anonymous
  • anonymous
oh let me check
dumbcow
  • dumbcow
hmm no you were right before
anonymous
  • anonymous
no I was correct firsdt time
anonymous
  • anonymous
yes , just went to check a high school maths study guide lying around
anonymous
  • anonymous
yes the first 1 is right
anonymous
  • anonymous
damm wikipedia, its usually a good resource for maths
anonymous
  • anonymous
but wikipedia shows the same formula u wrote at the first place :)
anonymous
  • anonymous
I can seem to find it, ahh I am bit tired
anonymous
  • anonymous
cant*
anonymous
  • anonymous
i am lost now lol
anonymous
  • anonymous
yes its for sure :)
anonymous
  • anonymous
\[\frac {a(1-r^n)}{1-r}\] sub in a=3, r=-3, n=10
anonymous
  • anonymous
3[1-(-3)^10]/1-3 =3[1-3^10]/2
anonymous
  • anonymous
so is the answer 1536?
anonymous
  • anonymous
???
anonymous
  • anonymous
u calculated it?does it come 1536?
anonymous
  • anonymous
yes that is what i got, is that what you got?
anonymous
  • anonymous
i dint calculate :)
anonymous
  • anonymous
oh ok... but does that make sense? my answer???
anonymous
  • anonymous
sure :)
anonymous
  • anonymous
lol ok thank you

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