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anonymous
 5 years ago
. Write the complex binomial expansion. (5x+3)^4
anonymous
 5 years ago
. Write the complex binomial expansion. (5x+3)^4

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dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0you have to know combinations like 4 choose1, 4 choose2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am so lost in this one....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(5x)^4+4(5x)^3 (3)+6(5x)^2(3)^2+4(5x)(3)^3+(3)^4 if i see it right; but what do you refer to as complex?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0with imaginary numbers? or simply complicated?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04C0 (5x)^4 + 4C1 (5x)^3 (3)^1 + 4C2 (5x)^2 (3)^2 + 4C3 (5x)^1 (3)^3 +4C4 (3^4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and im finished on here, going to go to sleep

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont know, thats what my problem says, exactly how i wrote it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0^ "with imaginary numbers"? thats not even possible. They wanted the binomail expansion , they want the binomial coefficents, not just pascals triangle

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0then elecs answer looks to be close to what they want :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so that long thing is the answer ? lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats what they mean by "complex"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04C0 (5x)^4 + 4C1 (5x)^3 (3)^1 + 4C2 (5x)^2 (3)^2 + 4C3 (5x)^1 (3)^3 +4C4 (3^4) This is the answer lol wow

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0I had parts of it right lol ;)

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0you need to multiply it out it will simplify a little bit

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im still in shock that thats the long answer lol

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0yeah the bigger the exponent, the longer the answer

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0where do we get the 4c1 and stuff from? the exponent?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0:) dint know if that was a fluke, or not :)

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.0no yours above was correct 4C1=4 4C2=6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so elecengineer answer was correst right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0....i wanna say yes, but I dont have a combinatorics button on the calulator ... :/

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0according to an online nCr calculator, mines good lol :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0but you prolly want the 4C0, 4C1 stuff

dumbcow
 5 years ago
Best ResponseYou've already chosen the best response.04C0 = 1 4C1=4 4C2=6 4C3 = 4 4C4=1 they just represent numbers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow this is way over my head
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