anonymous
  • anonymous
. Write the complex binomial expansion. (5x+3)^4
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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dumbcow
  • dumbcow
you have to know combinations like 4 choose1, 4 choose2
amistre64
  • amistre64
14641 might work?
anonymous
  • anonymous
i am so lost in this one....

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More answers

amistre64
  • amistre64
(5x)^4+4(5x)^3 (3)+6(5x)^2(3)^2+4(5x)(3)^3+(3)^4 if i see it right; but what do you refer to as complex?
amistre64
  • amistre64
with imaginary numbers? or simply complicated?
anonymous
  • anonymous
4C0 (5x)^4 + 4C1 (5x)^3 (3)^1 + 4C2 (5x)^2 (3)^2 + 4C3 (5x)^1 (3)^3 +4C4 (3^4)
anonymous
  • anonymous
and im finished on here, going to go to sleep
anonymous
  • anonymous
i dont know, thats what my problem says, exactly how i wrote it
anonymous
  • anonymous
^ "with imaginary numbers"? thats not even possible. They wanted the binomail expansion , they want the binomial coefficents, not just pascals triangle
amistre64
  • amistre64
then elecs answer looks to be close to what they want :)
anonymous
  • anonymous
so that long thing is the answer ? lol
anonymous
  • anonymous
thats what they mean by "complex"
anonymous
  • anonymous
4C0 (5x)^4 + 4C1 (5x)^3 (3)^1 + 4C2 (5x)^2 (3)^2 + 4C3 (5x)^1 (3)^3 +4C4 (3^4) This is the answer lol wow
amistre64
  • amistre64
I had parts of it right lol ;)
dumbcow
  • dumbcow
you need to multiply it out it will simplify a little bit
anonymous
  • anonymous
im still in shock that thats the long answer lol
dumbcow
  • dumbcow
yeah the bigger the exponent, the longer the answer
amistre64
  • amistre64
where do we get the 4c1 and stuff from? the exponent?
dumbcow
  • dumbcow
yes
amistre64
  • amistre64
:) dint know if that was a fluke, or not :)
dumbcow
  • dumbcow
no yours above was correct 4C1=4 4C2=6
anonymous
  • anonymous
so elecengineer answer was correst right?
amistre64
  • amistre64
....i wanna say yes, but I dont have a combinatorics button on the calulator ... :/
anonymous
  • anonymous
hmmm.... ok
amistre64
  • amistre64
according to an online nCr calculator, mines good lol :)
amistre64
  • amistre64
but you prolly want the 4C0, 4C1 stuff
dumbcow
  • dumbcow
4C0 = 1 4C1=4 4C2=6 4C3 = 4 4C4=1 they just represent numbers
dumbcow
  • dumbcow
nCr = n!/(n-r)!r!
anonymous
  • anonymous
wow this is way over my head

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