A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
. Write the complex binomial expansion. (5x+3)^4
anonymous
 5 years ago
. Write the complex binomial expansion. (5x+3)^4

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you have to know combinations like 4 choose1, 4 choose2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i am so lost in this one....

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0(5x)^4+4(5x)^3 (3)+6(5x)^2(3)^2+4(5x)(3)^3+(3)^4 if i see it right; but what do you refer to as complex?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0with imaginary numbers? or simply complicated?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04C0 (5x)^4 + 4C1 (5x)^3 (3)^1 + 4C2 (5x)^2 (3)^2 + 4C3 (5x)^1 (3)^3 +4C4 (3^4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and im finished on here, going to go to sleep

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i dont know, thats what my problem says, exactly how i wrote it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0^ "with imaginary numbers"? thats not even possible. They wanted the binomail expansion , they want the binomial coefficents, not just pascals triangle

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0then elecs answer looks to be close to what they want :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so that long thing is the answer ? lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats what they mean by "complex"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04C0 (5x)^4 + 4C1 (5x)^3 (3)^1 + 4C2 (5x)^2 (3)^2 + 4C3 (5x)^1 (3)^3 +4C4 (3^4) This is the answer lol wow

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0I had parts of it right lol ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you need to multiply it out it will simplify a little bit

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im still in shock that thats the long answer lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah the bigger the exponent, the longer the answer

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0where do we get the 4c1 and stuff from? the exponent?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0:) dint know if that was a fluke, or not :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no yours above was correct 4C1=4 4C2=6

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so elecengineer answer was correst right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0....i wanna say yes, but I dont have a combinatorics button on the calulator ... :/

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0according to an online nCr calculator, mines good lol :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0but you prolly want the 4C0, 4C1 stuff

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04C0 = 1 4C1=4 4C2=6 4C3 = 4 4C4=1 they just represent numbers

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow this is way over my head
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.