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anonymous
 5 years ago
find the integral S 9z square root 3z^27 dz
anonymous
 5 years ago
find the integral S 9z square root 3z^27 dz

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0First guess, your u is under the radical. Good indication your guess is right, du is outside radical.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Divide?! Do not pass go. Go back to square one. Are you familiar with integrating using u substitution method.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is what i have\[u: 3z ^{2}7 du: 1/3 \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[^9\int\limits_{}^{}\sqrt{u} = 1/3du = 9^{1/2}= 9u ^{3/2}/3/2 \times 1/3du =6u3/2 \times 1/3 =2(3z ^{2}7)^3/2 \]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0du=6z dz du/6=z Don't concern yourself with trying to cancel the 9. It is just a constant and you can bring it front of the integral sign. It seems like you have been distracted by the 9 and did not get the correct derivative of u.
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