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anonymous
 5 years ago
Use the chain rule to find dy/dx for the given value of x.
y= (u1/u+1)^1/2
u= sqrt x1; for x= 34/9
I got to 1/2 (u1/u+1)^1/2. Do I need to do quotient rule also?
anonymous
 5 years ago
Use the chain rule to find dy/dx for the given value of x. y= (u1/u+1)^1/2 u= sqrt x1; for x= 34/9 I got to 1/2 (u1/u+1)^1/2. Do I need to do quotient rule also?

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0the chain rule implies it by this problem yes. dy dy du  =   dx du dx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so after the step that I have, do the quotient rule next

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0y = m^2 ; dy/dm = 2m m = (u1/u+1); dm/du = derivative rule u = sqrt(x1) ; du/dx = 1/2sqrt(x1) dy/dx = dy/dm * dm/du * du/dx

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0opps y = m^(1/2); dy/dm = 1/2sqrt(m)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{1}{2(\frac{\sqrt{x1}+1}{\sqrt{x1}1})} * \frac{(\sqrt{x1}+1)(\frac{1}{2 \sqrt{x1}})(\sqrt{x1}1)(\frac{1}{2 \sqrt{x1}})}{(\sqrt{x1}+1)^2} * \frac{1}{2 \sqrt{x1}}\]
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