ok how to find the area ??

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

ok how to find the area ??

Mathematics
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

1 Attachment
integrate :) the trick is, does your material say to keep (-) areas negative or not....
ok i did that

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

but i get confuse what points show i use
\[F(x) = \int\limits_{0}^{3} (x^3 -4x) dx \rightarrow F(x)=\frac{x^4}{4} - \frac{4x^2}{2} |_{0}^{3}\]
ok
Area = F(3) - F(0) F(0) = 0 F(3) = 81/4 - 36
22'3/4 - 36 = -13' 1/4..... so that should be the area
it aint cause I forgot how to multiply lol
(3)^4 ---- - 2(3)^2 4
22' 3/4 - 18 = 4' 3/4...right?
i have -135/4
ack!!...someone get me a calculator lol
lol
2.25.... and thats my final offer :) How you coming up with -135/4?
i mixed my #s lol but i have 9/4
20' 1/4 ------ 4 | 81 -8 ----- 1 -0 --- 1 <- remainder
9/4 is good :)
ok:D
20' 1/4 -18 -------- 2' 1/4 = 9/4
sweet! :D

Not the answer you are looking for?

Search for more explanations.

Ask your own question