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anonymous
 5 years ago
ok how to find the area ??
anonymous
 5 years ago
ok how to find the area ??

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1integrate :) the trick is, does your material say to keep () areas negative or not....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but i get confuse what points show i use

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1\[F(x) = \int\limits_{0}^{3} (x^3 4x) dx \rightarrow F(x)=\frac{x^4}{4}  \frac{4x^2}{2} _{0}^{3}\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1Area = F(3)  F(0) F(0) = 0 F(3) = 81/4  36

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.122'3/4  36 = 13' 1/4..... so that should be the area

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1it aint cause I forgot how to multiply lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1(3)^4   2(3)^2 4

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.122' 3/4  18 = 4' 3/4...right?

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.1ack!!...someone get me a calculator lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.12.25.... and thats my final offer :) How you coming up with 135/4?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i mixed my #s lol but i have 9/4

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.120' 1/4  4  81 8  1 0  1 < remainder

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.120' 1/4 18  2' 1/4 = 9/4
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