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anonymous
 5 years ago
what is the derivative of (lnx^2)/(x+1)^(1/2)
anonymous
 5 years ago
what is the derivative of (lnx^2)/(x+1)^(1/2)

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0\[D_x(\frac{\ln(x)}{(x+1)^2})\]

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0this thing? and whered my fraction bar end up :)

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0use quotient rule; or bring the botom up with a negative exponent and use product rule

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0murmuring..... ^(1/2) lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0bt'b't f'(x) =  b^2

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0b = (x+1)^(1/2) ; b' = 1/[2(x+1)^(1/2)] t = ln(x) ; t' = 1/x

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0b^2 = (x+1) :) that one was easy lol

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0\[\frac{\frac{\sqrt{x+1}}{x}  \frac{\ln(x)}{2 \sqrt{x+1}}}{(x+1)}\] simplify as needed

amistre64
 5 years ago
Best ResponseYou've already chosen the best response.02x + 2  x ln(x)  2x(x+1) sqrt(x+1)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0amistre64, In the following equation, Ln is spelled Log. \[\int\limits \frac{\frac{\sqrt{1+x}}{x}\frac{\text{Log}[x]}{2 \sqrt{1+x}}}{1+x} \, dx = \frac{\text{Log}[x]}{\sqrt{1+x}} \] It looks to me like the Ln of x was raised to the second power in the original problem statement above. Perhaps by eyes are failing me in my old age.
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