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anonymous

  • 5 years ago

how do you solve a vertical hyperbolas that looks like this : ( y^2-2y )-4(x^2 )= 36?

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  1. amistre64
    • 5 years ago
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    what do you mean by "solve"?

  2. amistre64
    • 5 years ago
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    (y^2-2y )-4(x^2 )= 36 complete the squares :)

  3. amistre64
    • 5 years ago
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    -4x^2 is already fine....nothing needed there y^2 -2y + _____ ; (-2/2)^2 = 1 y^2 -2y +1; since you add 1 to this side; add it to the other side as well....

  4. amistre64
    • 5 years ago
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    or is it just asking for the complete the square info?

  5. anonymous
    • 5 years ago
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    thank you

  6. anonymous
    • 5 years ago
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    its asking to complete the square info

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