You have a 3.00mL of a 500 mg/dl urea standard. How much water must be added to produce a final concentration of 200mg/dl?

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You have a 3.00mL of a 500 mg/dl urea standard. How much water must be added to produce a final concentration of 200mg/dl?

Mathematics
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mg = ..milligrams? dl =....got no clue lol
whats mg/dl mean?
milligrams per deciliter

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Other answers:

i suspected as much... :)
3 mL = .03 decaliters...
500*.03 = 15 500(.03) + 0(w) = 200(.03 + w) I assume
500 = 6 + 20w 496 = 20w 24.8 = w 24.8 decaliters of water if I did it right :)
2480 mL of water sound right to you?
seems a little high, since the standard was only 3.00mL
i see an error..... I did 20 and not 200; dropped an important zero :)
500 = 6 + 200w 496 = 200w 496/200 = w water = 2.48 dl which is 248 mL
..still off; i see another error :)
500*.03 = 15 15 = 6 + 200w 9 = 200w 9/200 = w 0.045 decaliters of water if I did it right this time... w = 4.5 mL ....better?
that seems correct!
lol ..... gonna have to recall alot of prescriptions after that :)
i appreciate it!
may i ask how you got the 6, in 15 = 6 + 200w?
Let t be the amount of chemical. Then t/3.00 = 500 => t = 1500 t/x = 200 => x = 1500/200 = 7.5 mL must be added
200*.03 = 6
No 3.5 must be added for total of 7.5
i figure we need a 200 solution that is a combonation of .03 and "water" 200(.03 + w) = 6 + 200w ..... not that the equation is right to begin with :)
Shoot 4.5 added to the original 3.0 to get 7.5
ivan..lol; was I right :)
yep both ways work, i appreciate the help!
This is why I suck on a test
the math I can do....sometimes, when the moon is full and the butterflies are dancing among the daisies that is :)
i've got a few more, i'll post questions, walking me through that made so much more sense
You must change mine to be kosher t/(3.00+ x) = 1500 => .... x = 4.5
Or you could introduce let new amount_new = 3.00 + x Then t/amount_new = 200 or Amount_new = 1500/200 =7.5 => x = 7.5 - 3.0 = 4.5
Thanks!

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