You have 1.50mL of a urine specimen. The assay you must do requires a 1/25 dilution. How much water must be added to the specimen to achieve this dilution?

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You have 1.50mL of a urine specimen. The assay you must do requires a 1/25 dilution. How much water must be added to the specimen to achieve this dilution?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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urine? eww!!!
1/25 = .04 as a decimaled percent. 1.5(1) + y(0) = (1.5+y)(.04)
1.5 = .06 + .04y 1.5 - .06 = .04y y = 1.44/.04 = 144/4 = 36 36mL of water...and some soap?

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hahaha. thank you :)
i did get 36 as well!
yay!! we shuld join mensa :)

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