find the derivative of : f(x)=2sin(e^x)ln(sqrt(x))

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find the derivative of : f(x)=2sin(e^x)ln(sqrt(x))

Mathematics
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Eww, that's a gross derivative. Know how product rule and chain rule work?
Yes I have the result I would just like someone to compute it to check against/ask why I got something different if that occurred.
All right, give me a minute.

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Other answers:

kk ty
2e^x*sin(e^x)*lnsqrt(x)+2sin(e^x)*1/x
Sorry, that should be 1/(2x) at the end.
Is that what you got?
\[sine(e^x)/x + 2\cos(e^x)*e^x*\ln \sqrt{x}\] is the correct answer
I had forgotten to derive the sin, it's actually 2*e^x*cos(e^x)*ln(sqrt(x))+2*sin(e^x)*1/(2*x) The answer that you had didn't use chain rule for ln(sqrt(x)), you just took the derivative of ln x.
You do realize log(sqrt(x)) = 1/2log(x)? I simply did some algebra before integration. Nonetheless your 2nd result is the result I posted.
Yeah, you're right.
Thx for the response though sir.
Not a problem.

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