At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
Solve for one variable and then plug that in to the other equation to get an equation with one unknown.
ok can you please help me more with that
Ok so I would take -6x+y=26 and solve for y and then plug that into 2x+9y=66 for y and solve for x.
Well that being said I got y=6x=26 for the y= and for the x= I got y/6-13/3 is that correct cause I am not positive
Not quite sure what you did, but I'll start working it out. Maybe you can see it that way. :)
y=6x+26 so then the other equation becomes 2x+9(6x+26)=66
Can you solve for x from there?
Yahtzee! Now plug in -3 for x into let's say y=6x+26 to get the y value. Then your ordered pair is (x,y)
-3,8 is the order pair
So how do you know which equation to put in so that you get the right answer or does it work with both?
It will work with both.
I hope that is right I gave you a medal for that thanks a bunch I am trying to learn this math and it is not easy to me but I am welling to set here til I can work it out with someone
That was correct thanks again!!!!!
Thanks. It is right :) Solving systems of equations by substitution method is the same process every time. No problem.