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anonymous
 5 years ago
continuously compounded interest, A=Pe^rt, where p is the principal, r is the annual interest rate, and t is the time in years..
If sarita deposits $1000 in an account paying 3.4% annual interest compounded continuously, what is the balance in the account after 5 years?
anonymous
 5 years ago
continuously compounded interest, A=Pe^rt, where p is the principal, r is the annual interest rate, and t is the time in years.. If sarita deposits $1000 in an account paying 3.4% annual interest compounded continuously, what is the balance in the account after 5 years?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Plug and chug. P is $1000, r is the rate so .034, and t is 5. A is what you are looking for.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So just plug that in.. equals to be $5172.92, thank you.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes just plug it in, but that number is wrong.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[A=1000e^.17\] where the .17 is from .034 x 5
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