A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • 5 years ago

there is a box of 20 munchkins that contains 5 jelly, 7 plain and 8 chocolate. Your friend chooses one and eats it. The you choose one and eat it a. draw a tree diagram to shall ALL the different possible ways the experiment above could occur. Be sure to label the probability of each event occurring along the branched b. What is the probability you other will the pick the same type of munchkin? c. What is the probability you both eat a different munchkin?

  • This Question is Closed
  1. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    easy

  2. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    you can both either eat jelly, plain or chocolate

  3. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    for some notation J= jelly P=plain C=chocolate

  4. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so we can get either (JJ) OR ( PP) OR (CC)

  5. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    let P= probability function so P(XX) means the probability of getting XX

  6. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    P(JJ) = (5/20) x ( 4/19) P(PP) = (7/20) x (6/19 ) --> hopefully you dont get confused with this notation, prob should have thought ahead. P(CC) = (8/20) x (7/19)

  7. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so for part b , you just add up all the probabilities above \\Answer = [ (5/20) x (4/19) ] + [ (7/20) x (6/19) ] + [ (8/20) x (7/19) ]

  8. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    then you can figure out on a calculator , I dont want to

  9. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    now for part c . Note: COMPLEMENTARY events. If they dont eat the same type , then they must have eaten different ones! so the probability ( eating different ) = 1 - probability ( eating the same ) so the answer to part c is ( 1- (answer of b ) )

  10. anonymous
    • 5 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    answer to b = 59/190 answer to c= 1 - ( 59/190) = 131/190

  11. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.