there is a box of 20 munchkins that contains 5 jelly, 7 plain and 8 chocolate. Your friend chooses one and eats it. The you choose one and eat it a. draw a tree diagram to shall ALL the different possible ways the experiment above could occur. Be sure to label the probability of each event occurring along the branched b. What is the probability you other will the pick the same type of munchkin? c. What is the probability you both eat a different munchkin?

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there is a box of 20 munchkins that contains 5 jelly, 7 plain and 8 chocolate. Your friend chooses one and eats it. The you choose one and eat it a. draw a tree diagram to shall ALL the different possible ways the experiment above could occur. Be sure to label the probability of each event occurring along the branched b. What is the probability you other will the pick the same type of munchkin? c. What is the probability you both eat a different munchkin?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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easy
you can both either eat jelly, plain or chocolate
for some notation J= jelly P=plain C=chocolate

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so we can get either (JJ) OR ( PP) OR (CC)
let P= probability function so P(XX) means the probability of getting XX
P(JJ) = (5/20) x ( 4/19) P(PP) = (7/20) x (6/19 ) --> hopefully you dont get confused with this notation, prob should have thought ahead. P(CC) = (8/20) x (7/19)
so for part b , you just add up all the probabilities above \\Answer = [ (5/20) x (4/19) ] + [ (7/20) x (6/19) ] + [ (8/20) x (7/19) ]
then you can figure out on a calculator , I dont want to
now for part c . Note: COMPLEMENTARY events. If they dont eat the same type , then they must have eaten different ones! so the probability ( eating different ) = 1 - probability ( eating the same ) so the answer to part c is ( 1- (answer of b ) )
answer to b = 59/190 answer to c= 1 - ( 59/190) = 131/190

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