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anonymous
 5 years ago
there is a box of 20 munchkins that contains 5 jelly, 7 plain and 8 chocolate. Your friend chooses one and eats it. The you choose one and eat it
a. draw a tree diagram to shall ALL the different possible ways the experiment above could occur. Be sure to label the probability of each event occurring along the branched
b. What is the probability you other will the pick the same type of munchkin?
c. What is the probability you both eat a different munchkin?
anonymous
 5 years ago
there is a box of 20 munchkins that contains 5 jelly, 7 plain and 8 chocolate. Your friend chooses one and eats it. The you choose one and eat it a. draw a tree diagram to shall ALL the different possible ways the experiment above could occur. Be sure to label the probability of each event occurring along the branched b. What is the probability you other will the pick the same type of munchkin? c. What is the probability you both eat a different munchkin?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can both either eat jelly, plain or chocolate

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0for some notation J= jelly P=plain C=chocolate

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so we can get either (JJ) OR ( PP) OR (CC)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0let P= probability function so P(XX) means the probability of getting XX

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0P(JJ) = (5/20) x ( 4/19) P(PP) = (7/20) x (6/19 ) > hopefully you dont get confused with this notation, prob should have thought ahead. P(CC) = (8/20) x (7/19)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so for part b , you just add up all the probabilities above \\Answer = [ (5/20) x (4/19) ] + [ (7/20) x (6/19) ] + [ (8/20) x (7/19) ]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then you can figure out on a calculator , I dont want to

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now for part c . Note: COMPLEMENTARY events. If they dont eat the same type , then they must have eaten different ones! so the probability ( eating different ) = 1  probability ( eating the same ) so the answer to part c is ( 1 (answer of b ) )

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0answer to b = 59/190 answer to c= 1  ( 59/190) = 131/190
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