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anonymous

  • 5 years ago

The amount of radioactive substance y that remains after t years is given by the equation y=ae^kt, where a is the initial amount present and k is the decay constant for the radioactive substance. If a = 100, y=50, and k=-0.035, find t so far i have... 50=100e^-0.035(t), then what?

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  1. anonymous
    • 5 years ago
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    uhhhhhh?

  2. anonymous
    • 5 years ago
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    no idea?

  3. anonymous
    • 5 years ago
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    You set it up correctly, now just have to solve. Start by dividing both sides by 100.

  4. anonymous
    • 5 years ago
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    \[.5=e^-0.035(t)\]?

  5. anonymous
    • 5 years ago
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    Yes. Now you need to get the t by itself. Think inverse of the e function...

  6. anonymous
    • 5 years ago
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    uhmm..

  7. anonymous
    • 5 years ago
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    i'm sorry i really have no idea. I get everything in the classroom and then when i get home and doing homework i get so lost.

  8. anonymous
    • 5 years ago
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    Ok ln is the inverse of e. So if we take the ln of both sides we get ln(.5)=-.035t sorry for a later response...

  9. anonymous
    • 5 years ago
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    thats okay.

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