anonymous
  • anonymous
Find the rectangular coordinates for the point whose polar coordinates are given. (6√2, 5π/3)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[x=rcos(\theta) , y=rsin(\theta)\]
anonymous
  • anonymous
\[ \sin(5\pi/3) = \sin(\pi/3) = (\frac{\sqrt{3}}{2})\]
anonymous
  • anonymous
For (6sqrt2))cos(5pi/3) I get 4.242640607. Do I round that up or what else?

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More answers

anonymous
  • anonymous
what form do i put it in
anonymous
  • anonymous
\[\cos(5\pi/3) = - \cos(\pi/3) = -\frac{1}{2}\]
anonymous
  • anonymous
you can get exact values!,
anonymous
  • anonymous
they want exact values
anonymous
  • anonymous
do i not put the 6sqrt2 in the front
anonymous
  • anonymous
yeah, exact values
anonymous
  • anonymous
no, I was just finding the angles
anonymous
  • anonymous
the answers u gave are wrong.
anonymous
  • anonymous
is 1/2 the x value? and sqrt3/2 y
anonymous
  • anonymous
\[ x =-6\sqrt{2} \frac{1}{2} , y= 6\sqrt{2}\frac{\sqrt{3}}{2}\]
anonymous
  • anonymous
lol plz dont tell u you put them in :(
anonymous
  • anonymous
^ thats the FINAL answer
anonymous
  • anonymous
i did.
anonymous
  • anonymous
well simplify it a bit
anonymous
  • anonymous
x = -3sqrt(2) , y= 3sqrt(6)
anonymous
  • anonymous
the answer for x seems very obscure
anonymous
  • anonymous
the other one's r wrong to
anonymous
  • anonymous
no their not
anonymous
  • anonymous
that's what the my hw program says. i hate it :P
amistre64
  • amistre64
x = 3sqrt(2) y = -3sqrt(6)
anonymous
  • anonymous
no,
amistre64
  • amistre64
5[pi/3 is in the 4th quadrant; +x, -y
anonymous
  • anonymous
wait lols , maybe
amistre64
  • amistre64
360-60 :)
anonymous
  • anonymous
yeh I was thinking 2pi/3 :|
anonymous
  • anonymous
amistre to the rescue: Thank you for all ur help eng :)
amistre64
  • amistre64
elec did al the hard stuff; got rid of the errors I would have done lol

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