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anonymous

  • 5 years ago

solve the quadratic equation by using the definition of square root and write the solution in radical form.

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  1. anonymous
    • 5 years ago
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    \[6y ^{2}=72\]

  2. anonymous
    • 5 years ago
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    Divide by 6 and take the square root.

  3. anonymous
    • 5 years ago
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    i'm stuck at 6y=\[\sqrt{12}\] does it turn into 1 +/- square(2)?

  4. anonymous
    • 5 years ago
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    You should get \[y^2=12\] when you divide both sides by 6.

  5. anonymous
    • 5 years ago
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    ohhh oops, yep yep.

  6. anonymous
    • 5 years ago
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    there are 2 answers though .

  7. anonymous
    • 5 years ago
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    Yes. So then take the square root of both sides....\[y=\pm \sqrt{12}\] Take note of the +/-

  8. anonymous
    • 5 years ago
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    right. ok thanks!

  9. anonymous
    • 5 years ago
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    And then either leave it that way or reduce. You're welcome. :)

  10. anonymous
    • 5 years ago
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    ohh i wonder if it will need to be reduced.. ?

  11. anonymous
    • 5 years ago
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    it says to simplify the solution

  12. anonymous
    • 5 years ago
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    So yes \[y=\pm \sqrt{4x3}\] where x means to multiply. Then the square root of 4 is 2 so we can bring that outside the square root symbol. Thus \[y=\pm2\sqrt{3}\]

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spraguer (Moderator)
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