## anonymous 5 years ago solve the quadratic equation by using the definition of square root and write the solution in radical form.

1. anonymous

$6y ^{2}=72$

2. anonymous

Divide by 6 and take the square root.

3. anonymous

i'm stuck at 6y=$\sqrt{12}$ does it turn into 1 +/- square(2)?

4. anonymous

You should get $y^2=12$ when you divide both sides by 6.

5. anonymous

ohhh oops, yep yep.

6. anonymous

there are 2 answers though .

7. anonymous

Yes. So then take the square root of both sides....$y=\pm \sqrt{12}$ Take note of the +/-

8. anonymous

right. ok thanks!

9. anonymous

And then either leave it that way or reduce. You're welcome. :)

10. anonymous

ohh i wonder if it will need to be reduced.. ?

11. anonymous

it says to simplify the solution

12. anonymous

So yes $y=\pm \sqrt{4x3}$ where x means to multiply. Then the square root of 4 is 2 so we can bring that outside the square root symbol. Thus $y=\pm2\sqrt{3}$