The perimeter of a rectangle is 38m. The length is 10m more than twice the width. Find the demensions. What is the lenght? ?=m Simplify your answer

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The perimeter of a rectangle is 38m. The length is 10m more than twice the width. Find the demensions. What is the lenght? ?=m Simplify your answer

Mathematics
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6
sorry, 16m
thanks

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Other answers:

try setting up the equations: you know that the perimeter of a box is twice the length + twice the width
so let's use w for width and l for length we have that 2w+2l = 38
but you are told that the length is 10 more than twice the width...so can you write that in equation form? i'll get you started.... length = 2 times width plus 10 (<=== write that in equation form)
what is the width I got -L+19
so you have w = -L + 19?
try plugging in your length...we know length is equal to 16
what do you get?
so... w = -(16) + 19 = ?
3
correct test your answer...does everything work out?
remember our original idea....that 2*length + 2*width = 38, your perimeter

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