## anonymous 5 years ago 6÷2(1+2)=?

1. anonymous

2. myininaya

6dividedby2(3) 3(3) 9

3. anonymous

If only...

4. anonymous

1?

5. anonymous

Yes.

6. myininaya

no 9

7. myininaya

use order of operations

8. anonymous

Yeah, parenthesis first.

9. myininaya

the multiplication and division as it occurs left to right

10. myininaya

then not the

11. myininaya

division occurs first so 6 divided by 2=3 and then multiplication occurs 3(3)=9

12. anonymous

Yeah, yeah 9 we get it haha. No really, no lie. it is 9. 1 is common mistake, because of the whole pemdas.

13. myininaya

lol

14. myininaya

hey loco you figured out your polar question?

15. anonymous

6/2(1+2) =6/2(3) =3(3) =9

16. anonymous

not yet myininaya

17. anonymous

i need help really badly with it :(

18. anonymous

The one I was attempting to help on loco?

19. myininaya

did you try ising (x=rcos(pheta),y=rsin(pheta))

20. anonymous

yeah, but the answers i get are decimals and they don't work and i don't know how to get the exact value.

21. myininaya

deciamls? thats weird shouldn't be decimals do you have your calculator in radians?

22. anonymous

yeah, should i put it in degrees?

23. myininaya

no put in degrees if you are using degrees but 15pi is in radians

24. myininaya

25. anonymous

Use a unit circle, not a calculator.

26. anonymous

I changed it to degrees, but the answer is still in decimals but the only thing is that it becomes negative.

27. myininaya

when i did I got (-1,0)

28. myininaya

right you could just use the unit circle

29. anonymous

how did u get that? can u show me

30. myininaya

thats what i did

31. anonymous

I would think it'd be much easier, avoid the calculator errors haha.

32. myininaya

cos(15pi)=cos(pi)=-1

33. myininaya

wait i forgot to multiply the 6 so it is (-6,0)

34. anonymous

(-1,0) are wrong says the hw program

35. anonymous

there we go that makes more sense

36. myininaya

lol

37. anonymous

no it's still wrong

38. myininaya

we are trying to evaluate (6cos(15pi)),6sin(15pi))

39. myininaya

what is it?

40. anonymous

(-6,0) is right.

41. anonymous

this is the original prob $6\sqrt{3}, -6$

42. anonymous

So the problem I tried helping you with?

43. myininaya

are we converting that to polar coordinates?

44. anonymous

Convert the rectangular coordinates to polar coordinates with r 0 and 0 θ 2π.$r>0 and 0 \le \theta <$

45. myininaya

ok i was doing converting (6,15pi) to polar my bad

46. myininaya

to cartesian*

47. anonymous

48. myininaya

(12, 7pi/6)

49. anonymous

Wouldn't it be (12, 11pi/6)

50. myininaya

you might be right one sec..

51. myininaya

darn it you are right because cos(11pi/6)=sqrt(3)/2

52. anonymous

thanks you so much for taking ur time to help me guys. i wish i could give u real medals :)

53. anonymous

I wish I could receive a real medal haha you're welcome.

54. myininaya

what loco i wanted to draw you something k?

55. anonymous

ok

56. anonymous

YESSSSSSSSSSSSSSSSSSSSSSSSSSSS!!! Finally :O

57. myininaya

58. myininaya

when I drew the point (6sqrt(3),-6) it was just an approximation of where it would lie.

59. anonymous

Wow... u did that much work. I feel bad now :(

60. myininaya

why? the only reason i would do is because i enjoy lol. but do you why we use that cos^-1(sqrt(3)/2) instead of the others

61. myininaya

because its where our point lies

62. anonymous

oh ok

63. myininaya

so you completely get it?

64. anonymous

not completely, some of it. don't worry i'll be awake all night trying to understand it.

65. anonymous

can u try to help me on the other question i posted?

66. myininaya

ok go to it and i will follow you k?

67. anonymous

ok