6÷2(1+2)=?

- anonymous

6÷2(1+2)=?

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- anonymous

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- myininaya

6dividedby2(3)
3(3)
9

- anonymous

If only...

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## More answers

- anonymous

1?

- anonymous

Yes.

- myininaya

no 9

- myininaya

use order of operations

- anonymous

Yeah, parenthesis first.

- myininaya

the multiplication and division as it occurs left to right

- myininaya

then not the

- myininaya

division occurs first so 6 divided by 2=3
and then multiplication occurs 3(3)=9

- anonymous

Yeah, yeah 9 we get it haha. No really, no lie. it is 9. 1 is common mistake, because of the whole pemdas.

- myininaya

lol

- myininaya

hey loco you figured out your polar question?

- anonymous

6/2(1+2)
=6/2(3)
=3(3)
=9

- anonymous

not yet myininaya

- anonymous

i need help really badly with it :(

- anonymous

The one I was attempting to help on loco?

- myininaya

did you try ising (x=rcos(pheta),y=rsin(pheta))

- anonymous

yeah, but the answers i get are decimals and they don't work and i don't know how to get the exact value.

- myininaya

deciamls?
thats weird shouldn't be decimals
do you have your calculator in radians?

- anonymous

yeah, should i put it in degrees?

- myininaya

no put in degrees if you are using degrees but 15pi is in radians

- myininaya

so we are using radians

- anonymous

Use a unit circle, not a calculator.

- anonymous

I changed it to degrees, but the answer is still in decimals but the only thing is that it becomes negative.

- myininaya

when i did I got (-1,0)

- myininaya

right you could just use the unit circle

- anonymous

how did u get that? can u show me

- myininaya

thats what i did

- anonymous

I would think it'd be much easier, avoid the calculator errors haha.

- myininaya

cos(15pi)=cos(pi)=-1

- myininaya

wait i forgot to multiply the 6 so it is (-6,0)

- anonymous

(-1,0) are wrong says the hw program

- anonymous

there we go that makes more sense

- myininaya

lol

- anonymous

no it's still wrong

- myininaya

we are trying to evaluate (6cos(15pi)),6sin(15pi))

- myininaya

what is it?

- anonymous

(-6,0) is right.

- anonymous

this is the original prob
\[6\sqrt{3}, -6\]

- anonymous

So the problem I tried helping you with?

- myininaya

are we converting that to polar coordinates?

- anonymous

Convert the rectangular coordinates to polar coordinates with r 0 and 0 θ 2π.\[r>0 and 0 \le \theta <\]

- myininaya

ok i was doing converting (6,15pi) to polar my bad

- myininaya

to cartesian*

- anonymous

I had everything pretty much outlined for you on your post loco, well besides the answer.

- myininaya

(12, 7pi/6)

- anonymous

Wouldn't it be (12, 11pi/6)

- myininaya

you might be right one sec..

- myininaya

darn it you are right because cos(11pi/6)=sqrt(3)/2

- anonymous

thanks you so much for taking ur time to help me guys. i wish i could give u real medals :)

- anonymous

I wish I could receive a real medal haha you're welcome.

- myininaya

what loco i wanted to draw you something k?

- anonymous

ok

- anonymous

YESSSSSSSSSSSSSSSSSSSSSSSSSSSS!!! Finally :O

- myininaya

##### 1 Attachment

- myininaya

when I drew the point (6sqrt(3),-6) it was just an approximation of where it would lie.

- anonymous

Wow... u did that much work. I feel bad now :(

- myininaya

why? the only reason i would do is because i enjoy lol.
but do you why we use that cos^-1(sqrt(3)/2) instead of the others

- myininaya

because its where our point lies

- anonymous

oh ok

- myininaya

so you completely get it?

- anonymous

not completely, some of it. don't worry i'll be awake all night trying to understand it.

- anonymous

can u try to help me on the other question i posted?

- myininaya

ok go to it and i will follow you k?

- anonymous

ok

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