anonymous
  • anonymous
want to make sure I solved this quadratic equation correctly..
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[-3^{2}-x+1=0\]
anonymous
  • anonymous
I got 1 +/- (sqroot 2)
anonymous
  • anonymous
i get -1/6 +/- sqrt(13)/6

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
lemme type what i did and you can see if i went wrong
anonymous
  • anonymous
\[[-(-1) \pm \sqrt{1-4(-3)1}]/(2(-3))\]
anonymous
  • anonymous
I probably did it wrong. So do you think those are 2 non real solutions? I need to indicate whether there are 2 different real solutions, 2 non real solutions, or 1 repeated real solution
anonymous
  • anonymous
There are 2 real solutions
anonymous
  • anonymous
oh ok. And the square root is only over the 13?
anonymous
  • anonymous
yeah
anonymous
  • anonymous
thanks!
anonymous
  • anonymous
yeahp lol

Looking for something else?

Not the answer you are looking for? Search for more explanations.