A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
Convert the equation to polar form.
5x=5y
AND
x^2+y^2=16
anonymous
 5 years ago
Convert the equation to polar form. 5x=5y AND x^2+y^2=16

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0x=r cosƟ, y=r sinƟ, x^2+y^2=r^2.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't get the second one. x^2+y^2=r^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No, not really. Trig and I don't get along at all

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1ok loco do you have that picture i drawed you where I graph (x,y) and called the angle between the initial ray and I guess we can call it the vector with endpoints at the origin and at the point (x,y)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, it's open in my pdf

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1k and I put inside a circle i called the radius of that circle r

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1that trangle is a right triangle so we can use Pythagorean them to find what r is in terms of x and y

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1or like anwar said before x^2+y^2=r^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, i don't this equation? what do i use it for?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1we want to convert x^2+y^2=16 to a polar equation so that means we want it in terms of r and pheta but what is x^2+y^2=.....?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1loco, do you know what to fill that blank with?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1if we are doing 5x^2+5y^2=16 then we can factor out 5 so we have 5(x^2+y^2)=16 but what does x^2+y^2=?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry, if i take too long, trying to figure this out

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.15r=16 is the polar equation of the cartesian equation 5x^2+5y^2=16

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1these equations give the same graph using a little different way of graphing

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1these are equations are equivalent

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1polar is in the form (r,pheta) Cartesian is in the form (x,y)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what do u mean equivalent? = to what? 16

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so 5x=5y, is that what u mean?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.15r=16 is equivalent to 5x^2+5y^2=16 because they are the same graph

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1so you want to convert 5x=5y to polar equation?

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1so remember polar has (r,pheta) form so x=rcos(pheta) and y=rsin(pheta) 5rcos(pheta)=5rsin(pheta) we could divide both sides by 5 so we have rcos(pheta)=rsin(pheta) rcos(pheta)rsin(pheta)=0 r(cos(pheta)sin(pheta))=0 so we have r=0 and cos(pheta)sin(pheta)=0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow... um.. let me try to figure all this out

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1hey i was talking to my hubby. hes gonna be home soon so I'm going to leave soon but we were done with writing 5x=5y to a polar equation

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1so did you have a question or something?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this might sound arrogant but, how do i set it up and how do i get the answer

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1how you have to do is place x^2+y^2 with r and replace x with rcos(pheta) and y with rsin(pheta) and usually I tried to simplified like I did above

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1write with no x and no y

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1your goal is to write with r and pheta

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1do you see my mistake way up there? i forgot r^2 when i wrote 5r^2=16 is equivalent to 5x^2+5y^2=16

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so it would be 5^2+5^2=

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1where did you get x=5 and y=5?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh.. crap. i got them from the original equation

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1hey anwar is going to come back and help you i have to leave k?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok thank you very much for all ur help though :)

myininaya
 5 years ago
Best ResponseYou've already chosen the best response.1i think you are over thinking this stuff

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i tend to do that a lot :P

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i got the whole night, don't worry i'll get it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Just gimme a minute. I'll help you when I finish with another question if you still need help.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't know where you have reached. But I'll start by these formula in polar coordinates: \[x=r \cos \theta .... (1)\] \[y=r \sin \theta .... (2)\] \[x^2+y^2=r^2 .... (3)\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We're trying to convert the given equations that are in terms of x and y to an a form in terms of r and theta, which is called polar coordinates. Is that clear so far?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Good, Now consider the first equation: 5x=5y. Divide both sides by 5 you get: \[x=y\] But we can substitute fot x with equation (1) and for y with equation (2). That's: \[x=y \implies r \cos \theta=r \sin \theta\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For the 2nd equation: \[x^2+y^2=16\] we will just apply directly the third formula, since x^2+y^2 is just r^2. Then: \[x^2+y^2=16 \implies r^2=16\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yep. You can simplify it more, but this is OK.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.