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x=r cosƟ, y=r sinƟ, x^2+y^2=r^2.

I don't get the second one. x^2+y^2=r^2

No, not really. Trig and I don't get along at all

yeah, it's open in my pdf

k and I put inside a circle i called the radius of that circle r

r=sqrt(x^2+y^2)

or like anwar said before x^2+y^2=r^2

yeah, i don't this equation? what do i use it for?

loco, do you know what to fill that blank with?

5x^2+5y^2=16

does it equal r?

right!

sorry, if i take too long, trying to figure this out

5r=16 is the polar equation of the cartesian equation 5x^2+5y^2=16

these equations give the same graph using a little different way of graphing

these are equations are equivalent

polar is in the form (r,pheta)
Cartesian is in the form (x,y)

what do u mean equivalent? = to what? 16

no to each other

so 5x=5y, is that what u mean?

5r=16 is equivalent to 5x^2+5y^2=16 because they are the same graph

oh ok...

so you want to convert 5x=5y to polar equation?

yes

wow... um.. let me try to figure all this out

ok

There?

yes

so did you have a question or something?

this might sound arrogant but, how do i set it up and how do i get the answer

all not how

write with no x and no y

your goal is to write with r and pheta

ok

x^2+y^2 with r^2*

do you see my mistake way up there?
i forgot r^2 when i wrote 5r^2=16 is equivalent to 5x^2+5y^2=16

so it would be 5^2+5^2=

where did you get x=5 and y=5?

oh.. crap. i got them from the original equation

hey anwar is going to come back and help you i have to leave k?

ok thank you very much for all ur help though :)

i think you are over thinking this stuff

i tend to do that a lot :P

i hope you get it

thank you

i got the whole night, don't worry i'll get it

Just gimme a minute. I'll help you when I finish with another question if you still need help.

ok

ok

Is is clear so far?

Is it*

is this the answer

Yep. You can simplify it more, but this is OK.