anonymous
  • anonymous
if i am looking for the derivative of f(x)=sin2x(3x+7)^5 would i come out with f'(x)=5(sin2x)^4(cos2)(6x+21)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
What do you guys think?
anonymous
  • anonymous
wrong, way off
anonymous
  • anonymous
there are many chain rules here...make sure you apply them

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anonymous
  • anonymous
and i'm assuming that's sin(2x) (3x+7)^5?
anonymous
  • anonymous
review your product rules...and go slowly =)
anonymous
  • anonymous
=sin2x du/dx = 2cos(2x) v= (3x+7)^5 dv/dx = 5 (3x+7)^4 * 3 = 15 (3x+7)^4 now product rule
anonymous
  • anonymous
Find the derivative of the function f(x) = sin 2x(3x + 7)^5
anonymous
  • anonymous
f'(x) = 2cos(2x)(3x+7)^5 + 15sin(2x) (3x+7)^4
anonymous
  • anonymous
thats copied from the guide
anonymous
  • anonymous
what elec wrote is correct...so please do it yourself and compare with what he wrote...there's no point copying the answer...make sure you know how he derived it
anonymous
  • anonymous
Thanks for the help
anonymous
  • anonymous
np, let me know if something seems fishy...it's better to do the leg work now....or you'll regret it later =)
anonymous
  • anonymous
Isn't the derivative of cos = -sin?
anonymous
  • anonymous
it is...but you are looking for the derivative of sine which is cosine
anonymous
  • anonymous
so... d/dx sin(x) = cos(x) d/dx cos(x) = -sin(x)
anonymous
  • anonymous
ok i see that now thanks, can you break down how he got the 15sin it looks to me that it would be 10sin(2x)(3x+7)^4
anonymous
  • anonymous
I may just be really really confused now
anonymous
  • anonymous
careful there you shouldn't be doing a chain rule on the sin(2x) ...you need to do it on the (3x+7)...so actually...you get 15sin(2x)(3x+7)^4
anonymous
  • anonymous
it might help to break up your function... f(x) = sin(2x) * (3x + 7)^5 = u(x) * v(x) f'(x) = u'(x)*v(x) + v'(x)*u(x) try to take it from here ( I let u(x) = sin(2x) and v(x) = (3x+7)^5 )
anonymous
  • anonymous
f'(x)=2cos2*(3x+7)^5+15x*sin(2x)(3x+7)^4
anonymous
  • anonymous
ok i caught it that time, thanks for the help
anonymous
  • anonymous
you are welcome

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