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anonymous
 5 years ago
if i am looking for the derivative of
f(x)=sin2x(3x+7)^5 would i come out with
f'(x)=5(sin2x)^4(cos2)(6x+21)
anonymous
 5 years ago
if i am looking for the derivative of f(x)=sin2x(3x+7)^5 would i come out with f'(x)=5(sin2x)^4(cos2)(6x+21)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What do you guys think?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there are many chain rules here...make sure you apply them

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and i'm assuming that's sin(2x) (3x+7)^5?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0review your product rules...and go slowly =)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0=sin2x du/dx = 2cos(2x) v= (3x+7)^5 dv/dx = 5 (3x+7)^4 * 3 = 15 (3x+7)^4 now product rule

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Find the derivative of the function f(x) = sin 2x(3x + 7)^5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f'(x) = 2cos(2x)(3x+7)^5 + 15sin(2x) (3x+7)^4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats copied from the guide

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what elec wrote is correct...so please do it yourself and compare with what he wrote...there's no point copying the answer...make sure you know how he derived it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0np, let me know if something seems fishy...it's better to do the leg work now....or you'll regret it later =)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Isn't the derivative of cos = sin?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is...but you are looking for the derivative of sine which is cosine

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so... d/dx sin(x) = cos(x) d/dx cos(x) = sin(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok i see that now thanks, can you break down how he got the 15sin it looks to me that it would be 10sin(2x)(3x+7)^4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I may just be really really confused now

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0careful there you shouldn't be doing a chain rule on the sin(2x) ...you need to do it on the (3x+7)...so actually...you get 15sin(2x)(3x+7)^4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it might help to break up your function... f(x) = sin(2x) * (3x + 7)^5 = u(x) * v(x) f'(x) = u'(x)*v(x) + v'(x)*u(x) try to take it from here ( I let u(x) = sin(2x) and v(x) = (3x+7)^5 )

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0f'(x)=2cos2*(3x+7)^5+15x*sin(2x)(3x+7)^4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok i caught it that time, thanks for the help
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