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anonymous

  • 5 years ago

can some give me the steps to solve this problem 7e^4x+1=28

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  1. anonymous
    • 5 years ago
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    First you want to subtract the 1 over and then divide by 7. So you will have e^4x=27/7 Then to get rid of the e, you natural log both sides. So you get 4x=ln(27/7) Then finally, x=(ln(27/7))/4

  2. anonymous
    • 5 years ago
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    okay, I was dividing both sides by 7 first

  3. anonymous
    • 5 years ago
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    That would work, you'd just have to make sure that you also divide that 1 by 7. It's usually just simpler to combine constants first.

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