can some give me the steps to solve this problem 7e^4x+1=28

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can some give me the steps to solve this problem 7e^4x+1=28

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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First you want to subtract the 1 over and then divide by 7. So you will have e^4x=27/7 Then to get rid of the e, you natural log both sides. So you get 4x=ln(27/7) Then finally, x=(ln(27/7))/4
okay, I was dividing both sides by 7 first
That would work, you'd just have to make sure that you also divide that 1 by 7. It's usually just simpler to combine constants first.

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