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anonymous
 5 years ago
an arrow is shot vertically upward from a platform of 25 ft high at a rate of 153 ft per second. When will the arrow hit the ground?
anonymous
 5 years ago
an arrow is shot vertically upward from a platform of 25 ft high at a rate of 153 ft per second. When will the arrow hit the ground?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So we are using gravity as the force right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Integrate velocity to get the speed, out in the relation for the force of gravity, c is the original height, and solve

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0velocity is speed but with direction....

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[h=16t ^{2}+v _{0}t+h _{0}\] this is the formula

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm just have trouble working it out. so I wanted to see if anyone else could get an answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Use the kinematics formulas in order to solve this with a= 9.8 m/ s^2

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, set that equal to zero to find the maximum height and the time qt which it occurs. Then you can find out how long it takes for the arrow to fall.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is not that complicated. to solve this equation you will write: h=16t^2+153t+25

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You have all the variables given, except for t, which is what you're looking for.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Please post all the information in the question. Disregard my previous statements.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0v_0=153ft/sec, h=0, h_0=25ft.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Just substitute and solve for t.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you guys are making this seem way more complicated. h=16t^2+153t+25. set h to zero. you get 0=16t^2+153t+25, then solve for t.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah, maph... I said that a while ago lol.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[0=16t^2+153t+25 \implies t=9.7\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I only took the positive value for t.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ok I was doing it right. Just wanted to double check. thanks for the help everyone

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.09.7 is rounded to the nearest 10th right?
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