an arrow is shot vertically upward from a platform of 25 ft high at a rate of 153 ft per second. When will the arrow hit the ground?

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an arrow is shot vertically upward from a platform of 25 ft high at a rate of 153 ft per second. When will the arrow hit the ground?

Mathematics
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So we are using gravity as the force right?
Integrate velocity to get the speed, out in the relation for the force of gravity, c is the original height, and solve
help me

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velocity is speed but with direction....
\[h=-16t ^{2}+v _{0}t+h _{0}\] this is the formula
I'm just have trouble working it out. so I wanted to see if anyone else could get an answer
Use the kinematics formulas in order to solve this with a= 9.8 m/ s^2
Yes, set that equal to zero to find the maximum height and the time qt which it occurs. Then you can find out how long it takes for the arrow to fall.
this is not that complicated. to solve this equation you will write: h=-16t^2+153t+25
You have all the variables given, except for t, which is what you're looking for.
Please post all the information in the question. Disregard my previous statements.
v_0=153ft/sec, h=0, h_0=25ft.
Just substitute and solve for t.
you guys are making this seem way more complicated. h=-16t^2+153t+25. set h to zero. you get 0=-16t^2+153t+25, then solve for t.
Yeah, maph... I said that a while ago lol.
\[0=-16t^2+153t+25 \implies t=9.7\]
I only took the positive value for t.
ok I was doing it right. Just wanted to double check. thanks for the help everyone
9.7 is rounded to the nearest 10th right?
Yes.

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