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anonymous

  • 5 years ago

an arrow is shot vertically upward from a platform of 25 ft high at a rate of 153 ft per second. When will the arrow hit the ground?

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  1. anonymous
    • 5 years ago
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    So we are using gravity as the force right?

  2. anonymous
    • 5 years ago
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    Integrate velocity to get the speed, out in the relation for the force of gravity, c is the original height, and solve

  3. anonymous
    • 5 years ago
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    help me

  4. anonymous
    • 5 years ago
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    velocity is speed but with direction....

  5. anonymous
    • 5 years ago
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    \[h=-16t ^{2}+v _{0}t+h _{0}\] this is the formula

  6. anonymous
    • 5 years ago
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    I'm just have trouble working it out. so I wanted to see if anyone else could get an answer

  7. anonymous
    • 5 years ago
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    Use the kinematics formulas in order to solve this with a= 9.8 m/ s^2

  8. anonymous
    • 5 years ago
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    Yes, set that equal to zero to find the maximum height and the time qt which it occurs. Then you can find out how long it takes for the arrow to fall.

  9. anonymous
    • 5 years ago
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    this is not that complicated. to solve this equation you will write: h=-16t^2+153t+25

  10. anonymous
    • 5 years ago
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    You have all the variables given, except for t, which is what you're looking for.

  11. anonymous
    • 5 years ago
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    Please post all the information in the question. Disregard my previous statements.

  12. anonymous
    • 5 years ago
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    v_0=153ft/sec, h=0, h_0=25ft.

  13. anonymous
    • 5 years ago
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    Just substitute and solve for t.

  14. anonymous
    • 5 years ago
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    you guys are making this seem way more complicated. h=-16t^2+153t+25. set h to zero. you get 0=-16t^2+153t+25, then solve for t.

  15. anonymous
    • 5 years ago
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    Yeah, maph... I said that a while ago lol.

  16. anonymous
    • 5 years ago
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    \[0=-16t^2+153t+25 \implies t=9.7\]

  17. anonymous
    • 5 years ago
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    I only took the positive value for t.

  18. anonymous
    • 5 years ago
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    ok I was doing it right. Just wanted to double check. thanks for the help everyone

  19. anonymous
    • 5 years ago
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    9.7 is rounded to the nearest 10th right?

  20. anonymous
    • 5 years ago
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    Yes.

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