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anonymous

  • 5 years ago

Determine if (3+i -2) is an eigenvector of the matrix (-1 -2 / 5 -7) .. not division but under the first to numbers

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  1. anonymous
    • 5 years ago
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    use the definition

  2. anonymous
    • 5 years ago
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    if you multiply them do you end up with a scalar multiple of the matrix you started with? ( I am fairly sure thats the definition from memory )

  3. anonymous
    • 5 years ago
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    snce there are complex numbers I dont think its possible

  4. anonymous
    • 5 years ago
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    Av = Yv

  5. anonymous
    • 5 years ago
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    oh and that -2 is under the i

  6. anonymous
    • 5 years ago
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    y is lamda?

  7. anonymous
    • 5 years ago
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    yeh

  8. anonymous
    • 5 years ago
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    lol

  9. anonymous
    • 5 years ago
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    so the vector with two components is ( ( 3+i) , -2 ) ?

  10. anonymous
    • 5 years ago
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    Well it's written as a matrix

  11. anonymous
    • 5 years ago
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    fairly sure answer is no

  12. anonymous
    • 5 years ago
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    Yes that is right. Did you just use the formula? How did you know it wasn't the vector?

  13. anonymous
    • 5 years ago
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    if you multiply them together you get ( -(7+i) , (1+5i) ) This is not a scalar multiple of the vector you started with

  14. anonymous
    • 5 years ago
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    Okay, so it can be a multiple?

  15. anonymous
    • 5 years ago
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    no

  16. anonymous
    • 5 years ago
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    \[Av=\lambda v\] thats the definiton

  17. anonymous
    • 5 years ago
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    we multplied the two component vector with the matrix , and we didnt get a scalar multiple of the original vector , it doesnt satisfy the definition

  18. anonymous
    • 5 years ago
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    Oh okay, thank you!

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