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anonymous

  • 5 years ago

does anyone understand how to solve quadric equations how factoring is used to solve quadratic equations. Demonstrate the process with an example.

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  1. anonymous
    • 5 years ago
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    The general form of the quadratic eqn is ax^2 + bx +c

  2. anonymous
    • 5 years ago
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    We first take the product of a and c , keeping in mind their + or - sign

  3. anonymous
    • 5 years ago
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    then we find two numbers, say p and q, such that p x q = ac and p + q = b

  4. anonymous
    • 5 years ago
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    Then we substitute bx by px + qx in the eqn and then find factors

  5. anonymous
    • 5 years ago
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    Understood till now???

  6. anonymous
    • 5 years ago
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    for eg 2x^2 - 4x - 6 Here a=2 , b= -4 and c = -6

  7. anonymous
    • 5 years ago
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    Here a x c = 2 x -6 = -12 Now we have to break up -12 so that the two factors give product -12 and sum -4 Factors of 12 can be 1 x 12, 2 x 6, 3 x 4, Out of these, if we take the pair 2 x 6 and then modify it as 2 x -6, we get 2 x -6 = -12 and 2 + (-6) = -4 So, we can say 2x^2 -4x -6 = 2x^2 + 2x - 6x - 6 = 2x(x + 1) -6 (x + 1) Hence 2x^2 -4x -6 = (2x - 6) (x + 1)

  8. anonymous
    • 5 years ago
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    Hope this clears up factorisation for you!!

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