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anonymous
 5 years ago
How to find the center and radius given the standard equasion?
anonymous
 5 years ago
How to find the center and radius given the standard equasion?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0standard equation for a circle?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For a circle \[x^2+y^2+2gx+2fy+c=0\] , center is (g,f) and radius is \[\sqrt{g^2+f^2c}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Weird I've never seen that form for a circle. In most cases I see it as \[ax^2 + b^2= c^2\] where a=b where the radius is\[\sqrt{c^2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[ax^2+ by^2=c^2\] woops wrote it wrong.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Erm.. Standard equation for a circle is \[(xh)^2 + (yk)^2 = r^2\] If you put multiplicative constants out front that aren't equal you'll end up with an ellipse.
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