anonymous
  • anonymous
How to find the center and radius given the standard equasion?
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
standard equation for a circle?
anonymous
  • anonymous
For a circle \[x^2+y^2+2gx+2fy+c=0\] , center is (-g,-f) and radius is \[\sqrt{g^2+f^2-c}\]
anonymous
  • anonymous
Weird I've never seen that form for a circle. In most cases I see it as \[ax^2 + b^2= c^2\] where a=b where the radius is\[\sqrt{c^2}\]

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anonymous
  • anonymous
\[ax^2+ by^2=c^2\] woops wrote it wrong.
anonymous
  • anonymous
Erm.. Standard equation for a circle is \[(x-h)^2 + (y-k)^2 = r^2\] If you put multiplicative constants out front that aren't equal you'll end up with an ellipse.

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