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anonymous

  • 5 years ago

How to find the center and radius given the standard equasion?

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  1. anonymous
    • 5 years ago
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    standard equation for a circle?

  2. anonymous
    • 5 years ago
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    For a circle \[x^2+y^2+2gx+2fy+c=0\] , center is (-g,-f) and radius is \[\sqrt{g^2+f^2-c}\]

  3. anonymous
    • 5 years ago
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    Weird I've never seen that form for a circle. In most cases I see it as \[ax^2 + b^2= c^2\] where a=b where the radius is\[\sqrt{c^2}\]

  4. anonymous
    • 5 years ago
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    \[ax^2+ by^2=c^2\] woops wrote it wrong.

  5. anonymous
    • 5 years ago
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    Erm.. Standard equation for a circle is \[(x-h)^2 + (y-k)^2 = r^2\] If you put multiplicative constants out front that aren't equal you'll end up with an ellipse.

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