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anonymous
 5 years ago
Factor
4sˆ5+16s³32s20
4s^5 is suppose to be 4s exponent5 but i dont know how to do it
anonymous
 5 years ago
Factor 4sˆ5+16s³32s20 4s^5 is suppose to be 4s exponent5 but i dont know how to do it

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What have you done so far?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well, do you know how to find the factors of each term?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That is a start. Pull a factor of 4 from each term and see what you have left.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No, I mean write the new expression after you factor out a 4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Not quite. You're missing a s^5, but otherwise that's good.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now what other factors do some of your terms have in common?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, so factor those out from the terms that have it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0show me step by step plz and then explain

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How did you factor out the 4?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Right, but I mean what did you do?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Also that's not right

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0divide each term by 4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You keep forgetting the 4s^5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then what would it be

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04(s^5 +4s^3  8s  5)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But as I said, you can factor an s from the first 3 terms inside the parens.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Or rather, like you said.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And you would do it the same way. Put an s out front, and divide each term by the s you took away.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Just don't take one away from the term that doesn't have an s to start with.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No. What is \[\frac{s^5}{s}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0idk im really bad with fractions

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Then you should practice! =) Everything depends on everything else. If you practice your fractions until you are not bad with them, factoring will be a very fast process.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Lets start now. What is \[\frac{32}{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, and if I said \[\frac{2^5}{2}\] ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Interesting. And what was \[\frac{32}{2} \] again?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Right.. Just curious, but what is 2^4?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's interesting. \[\frac{2^5}{2} = 2^4\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Does this work with other numbers? \[3^3 = 27\] \[\frac{27}{3} =\ ?\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Lets see if we can figure out why this might be happening.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Or better still, \(a^3\)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, now if we have \[\frac{a\cdot a\cdot a}{a}\] We can cancel one of the a's on top with the a on the bottom. So what would that equal?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Right. So now, coming back to the original question.. What is \[\frac{s^5}{s}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What was \[\frac{a^3}{a}\] again?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No, you just said it 6 mins ago. just scroll up

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And do you remember why?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0because we cancel out 1

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So now. What is \[\frac{s^5}{s}\] Use the same argument as before

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So if we divide s^5 by s, we get s^4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And if we divide s^3 by s?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And if we divide s by s?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0that's a good reason.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats why i said s i thought instead of putting 1 you put the variable

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If we need to factor an s from s^5 +4s^3  8s what will our expression be?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0factor out an s, does that effect the numbers out in front?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so where'd the 4 go when you factored?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Where'd that 5 come from?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the original equation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That 5 didn't have an s

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So we cannot factor a s from it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Our original expression is \[4( s^5 + 4s^3 8s 5)\] And you said that \[s^5 + 4s^3 8s = s(s^4 + 4s^2 8)\] Right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes what happens to the 5

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0We leave it alone. We are going to replace \[s^5 + 4s^3 8s\] in the original expression with \[s(s^4 + 4s^2 8)\] What does it look like?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What is the original equation (after we factored out the 4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Right. So now take all those terms with an s, and replace them with the factored form you found.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Where'd the 4 out front go?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No. Take a second. Look at the original equation \[4(s^5+4s^38s5)\] I want you to retype this equation with a [ and a ] around the terms with an s.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0hrm. I think there's a vocab problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I realize this has been a very lengthy process, but bear with me for a min

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0im really bad at math

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I want you to know. You can be very good at math. You have the skills. You are a very hard worker clearly.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it just doesnt make sense to me

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I know that, but it's not for the reasons you think.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Somewhere a long time ago, you were learning math. And there were other classes, and due dates, or other life events, and somewhere along the way you missed something here and there. Not a lot, just a little bit. But it was a little bit here, and a little bit there, and slowly over time these little bits add up. They are not hard things to learn. But now you are expected to know them and they are holes in your knowlege. And these holes are making it 100 times harder to learn this new material.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So lets fill a few holes quickly

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I promise it will make math less hard

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And I assume that you have a reason for taking the math classes you are taking

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and don't want to give up on those goals

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Believe me. You can learn this.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i drop out in 9th grade got my GED and somehow passed the math test

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.012yrs ago i dropped out and got GED 1yr ago

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sounds like my story ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Except I graduated, but not with terribly good grades. Then screwed around for 15 years before finally going back to school

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i had my son dropped out and raised him and had my daughter and dont want to wait anymore

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah so how do i make this easier

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So lets learn some math. =)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Starting with vocabulary

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Vocabulary is important, because that way when I say something you can know exactly what I mean.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can we finish the problem we were working on first so i can close my homework this is the last problem

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But you weren't understanding what I was saying

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0First off, we have a sum. This is a sum: a + b + c

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0This sum has how many terms?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A term is just the things you are summing together.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How many terms are in the sum: a+b+c ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And how many terms are in the sum a*b + c +d*e

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How many different things are we adding together?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes. There are 3 things being added together. Those things are called terms.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now this is a product: a*b

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What are the factors of this product?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So how many factors are there?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok now 5  3a + 8c Is that a product, or a sum?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'd rather say it was a sum with one negative term

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How many terms are in this sum?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How many different things are being added (and subtracted) together?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Why do you keep breaking it up with repeated parts?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is 5  3 + 2 = 5  3 and 3+2 ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So what do you mean 53a 3a + 8c ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.05  3 + 2 Has how many terms?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Or if you prefer (5) + (3) + (2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How many things are being added together?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so each number is a term

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no, each thing you are adding together as part of the sum is a term

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a + b + c Has no numbers, but still has 3 terms

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so 4a+6b+8c is 3 or 6 terms

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0But! 4*3c + 7b + 4*12*7a Also has 3 terms

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What is the second term of the above expression?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, now going back to products

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you know that 7b is the same as 7*b yes?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think you're being trolled...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, so how many factors are in the product 7b?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, so what is \(7bc^2\) a sum, or a product?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, here's a trickier one. 4(a + 3) Sum or a product?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If I tell you that b = a+3 Wouldn't that expression be 4b ?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is 4b a sum or a product?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If 4b is a product, then 4(a+3) must be a product, cause they're basically the same expression

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So if 4b is a product, what are its factors?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No. The factors of 4b are 4, and b

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So if b = a+3 What are the factors of the product 4(a+3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What are the factors of 4b again?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, in the expression (the product) 4(a+3) What are the factors (things being multiplied together to form the product)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04(a+3) is 4 times (a+3) What two things are being multiplied!!?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The product 4(a+3) has 2 factors. They are 4 and (a+3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0One of those factors is a sum. Which one is a sum?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What are the terms of the sum (a+3)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(x+1)(x2) A product? or a sum?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(x+1) sum (x2) difference

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It is a product. (x+1)(x2) is (x+1) TIMES (x2) It is two things multiplied together.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Each of those two things by themselves is a sum, but when you multiply them together it's a product.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What is 4(s^5 + 4s^3  8s 5) A product? or a sum?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0What are the factors of this product?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now, the second factor has many terms with s in them

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I want you to find each term with a factor of s

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, now. Factor an s out of each of those terms, this will make a product where one factor is an s, and the other factor is the sum of the terms that you took the s from.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'm not sure where to begin there. You were doing well up until that point, so something about my instructions must not have made sense.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i just dont understand what you mean

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04 + 16 + 12 Factor a 4 from each of those terms.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04a + 3a + 2a Factor an a from each of those terms

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Why didn't you do the same thing you did for the 4?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i thought for the a's

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Just put an 'a' out front, and then divide each term by a.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No. We went over this before. s^5 divided by s is?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now take the terms in the original equation that you factored that s from, and put square brackets [] around them

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a) that is not the original equation b) the 4 out front is not one of the terms you took an s from

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you do not understand the instructions why don't you ask to clarify?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04s^5+16s^332s20 this is original equation where do i put the brackets i got s from all except the 20

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That is a very well thought out question. Thank you. I would like you to go to the form of the expression where we factored out the 4 already. Then place the brackets such that they surround ONLY the terms (from the sum) that you took the s from, and no others.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Realize that you haven't actually factored the s out yet. I just want you do denote which terms you will be taking the s from by placing them in the brackets

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0s(s^4+4s^28) this is where i factored the s

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0just guessing is [4+4][28] the answer you are looking for?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok This is the expression I want you to work with: \[4(s^5 + 4s^3  8s 5)\] Put square brackets around the terms that have s in them

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now, do you agree that s^5+4s^38s = s(s^4 + 4s^3  8) And that s^5+4s^38s is what is inside the brackets?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Good. Then delete what is inside the brackets and replace it with the version where the s is factored out. You should not change anything not inside the brackets.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0You didn't check my work ;p I made a mistake

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0It should be s(s^4 + 4s^2  8)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I had a 3 on the power of the middle term.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0where'd the s out in front go?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you changed something outside the brackets

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so then explain where im suppose to put the s that was in front

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Exactly where it was in the factored version. s(s^4 + 4s^2 8)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Delete what's in the brackets. Take that whole expression, and put it in the brackets instead.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Sure, that is at least correct.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0If you want, you can switch the brackets to parenthesis.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is that the right answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0almost. We still have more we can factor.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[4(s (s^4 + 4s^2  8)  5)\] There are two terms that have an \(s^2\)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04(s[s^4 + 4s^2 8)]5) is this what it should look like with the brackets

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes, except for the ) after the 8

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sry forgot to take that out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Which two terms in this expression have an s still?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The 4 is part of the term

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, so you can factor an s^2 from each of those terms s^4 + 4s^2 = s^2( ? + ? )

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0How did you factor out the 4, or the s, or anything else you've factored so far?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I can only assume you made some typos there, but you meant to have s^2(s^2 + 4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Ok, so replace those two terms (ONLY) with the newly factored version of the expression

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The two terms in the big expression we are working on.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0where did the s^2 out in front go?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0s^4 + 4s^3 = s^2(s^2 + 4) So take this [s^4 + 4s^3] and put in this [s^2(s^2 + 4)]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Err I miss typed that exponent again, but you know what I mean.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0s^4 + 4s^2 = s^2(s^2 + 4) Take out [ s^4 + 4s^2 ] Put in [ s^2(s^2 + 4) ]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04(s[s^2(s^2 + 4) 8]5)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes. exactly. the end.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0There are no terms that have any common factors, so we cannot factor anything else out anywhere.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.04(s[s^2(s^2 + 4) 8]5) this is the final answer

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes. Now I'm going to go do my math homework and go to bed before I have to get up in 5 hours.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i typed in the answer we came up with and it is wrong the answer is 4(s^5+4s^38s5) i had that 2 and 1/2 hrs ago

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0That's the problem with having a computer grade. The form we came up with is correct. You can factor it a lot of different ways. But "Factor" doesn't make it clear which bits to factor, or how far to factor.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0At a minimum the instructions should have been to factor using the greatest common factor.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0then at least you would know that the factorization you wanted would include all those terms.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0and also you learned a lot more about factoring from the extra practice.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes i did ty for everything
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