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\[x+2 \over x+6 \]>0

the x+2 is a fraction over x+6 and it's supposed to be in a straight line with >0

okay flip it.
so we get (x+6)/(x+2)>0
x+6 = x+2 +4
1+4/(x+2)>0
4/(x+2) > -1
4>(-x-2)
4<(x+2)

sorry the last step is -4 < x+2

got it?

The problem states you need to express it in both notations.

ohh I see what you were saying. ok. Thanks

lol, you are welcome.

for the interval notation.