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anonymous
 5 years ago
The second derivative of (4x^2)*exp(1.16x^2)
anonymous
 5 years ago
The second derivative of (4x^2)*exp(1.16x^2)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0can anyone help me with this?? =]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can use the product rule right?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0h(x)=f(x)g(x) h(x)=f(x)g(x)=f(x)g(x)+f(x)g(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0h'(x) = [f(x)g(x)]' = f'(x)g(x)+f(x)g'(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yes but it doesn't work. my online program does not accept it. (4x^2)(5.3824*^2*exp(1.16x^2)(2.32xexp(1.16x^2)(2x)(exp(1.16x^2)(2)(2x)(2.32xexp(1.16x^2)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0is that what you got?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I didn't work it out. I was just pointing out that you can use the product rule for this kind of problem.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i did. do you think you can check my work?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but your solution seems correct. see if you can simplify it further. Maybe your online tool will accept it then

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think I am getting a slightly different answer from you. check your calculations.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what is slightly different about it? I just double checked!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0did you simplify it. wait let me post my solution

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you can set x^2 = y and factor the second term.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0as a quadratic equation of course.
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