At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

need help..

still here?

yups

You need to find z in this set up given the info. you have.

You can find z by finding x, and you find x using the information you have about the rectangle.

The perimeter of the big square is equal to the perimeter of the rectangle.

ok..

I've called one side of one triangle h and the other k, so that x=h+k.

hmm..ya ok

Since sin(45)=z/h=z/k, we must have h=k, and so h+k=2h=18, which means h=9.

The area of the square is\[z^2=\frac{81}{2}\]

but lokisan i dont know trignometry...i am in
standard 9..

Hmmmm...let me see if there's another way.

yes please

Are you taught Pythagoras' Theorem? I don't know how the Indian system works.

yes

What are you currently learning? That might help me understand what your teacher's thinking.

mensuration

Are you 'allowed' to know that the diagonals of a square bisect the right angles?

no

man...

oh yes..
i understood

I know you understood...I'm just trying to stick to what you're allowed to know.

understanding has no restrictions ;) ,

yeah...have you covered congruence tests for triangles?

yeahh

Okay, I'll try and put something together with that.

ok

I might have something, but I want to double check.

hey i think i'hv got the answer ..it's coming to 648..is it correct..
??

hmm

okay..
thanks a lot .need to go and practice some more problems.will bug u if in need.thanx again

Oh...okay...anyway, I got \[z= \frac{\sqrt{648}}{3}\]so that the area is \[z^2=\frac{648}{9}=72\]

Congruent triangles and Pythagoras' Theorem were used.

yes

Cool...well, if you're happy, I'm happy :)