## anonymous 5 years ago Solve for x. log(7)*x+log(7)*(x-1)=log(7)*2x

1. anonymous

you'll get this :$\log_{7}x(x-1) = \log_{7} 2x$ but I'm not sure whether you're supposed to take the ln of both sides to get rid of the log

2. anonymous

when we have (+) and same log bases, then it means multiplication, and when we have (-) and same log bases then we divide ^_^

3. anonymous

but if you do take the ln of both sides then you'll get :$x^2-x=2x \rightarrow x^2-3x=0$$x(x-3) = 0$ so x = 0, 3 ^_^ but I'm not sure though

4. anonymous

wow i was totally over thinking it lol thank you sooo much

5. anonymous

np ^_^, but again not sure with the ln part :)