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anonymous
 5 years ago
Solve for x.
log(7)*x+log(7)*(x1)=log(7)*2x
anonymous
 5 years ago
Solve for x. log(7)*x+log(7)*(x1)=log(7)*2x

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you'll get this :\[\log_{7}x(x1) = \log_{7} 2x \] but I'm not sure whether you're supposed to take the ln of both sides to get rid of the log

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0when we have (+) and same log bases, then it means multiplication, and when we have () and same log bases then we divide ^_^

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but if you do take the ln of both sides then you'll get :\[x^2x=2x \rightarrow x^23x=0\]\[x(x3) = 0\] so x = 0, 3 ^_^ but I'm not sure though

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0wow i was totally over thinking it lol thank you sooo much

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0np ^_^, but again not sure with the ln part :)
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