anonymous
  • anonymous
Hi do anyone know how to do Rational Expressions. m+6/m^2-3m+2m-1/m^2+5m-14
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
is it :\[\frac{m+6}{m^2-3m} + \frac{2m-1}{m^2+5m-14}?\]
anonymous
  • anonymous
m+6m2−3m+2 +2m−1m2+5m−14 there's two (2)s but that setup is right
anonymous
  • anonymous
no fractions? lol I'm confused now

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anonymous
  • anonymous
lol yes fractions i just dont know how to put it on. its my first time on this. your set up is right. but you were missing a number 2 on m^2-3m+2 =)
anonymous
  • anonymous
try to put brackets for those with fractions :)
anonymous
  • anonymous
oh, so my equation was right? all I have to do is add a 2?
anonymous
  • anonymous
yes
anonymous
  • anonymous
okay :)
anonymous
  • anonymous
=) your soo awesome for helping me double =D
anonymous
  • anonymous
lol ^_^
anonymous
  • anonymous
thank you )
anonymous
  • anonymous
lol
anonymous
  • anonymous
alright, so after factoring the denominators we'll get:\[\frac{m+6}{(m-1)(m-2)} + \frac{2m-1}{(m+2)(m-7)}\] now get them to have the same denominators: \[\frac{(m+6)(m+2)(m-7) + (2m-1)(m-1)(m-2)}{(m+2)(m-2)(m-1)(m-7)}\]
anonymous
  • anonymous
hmmm, there's something wrong
anonymous
  • anonymous
are you sure of your question?
anonymous
  • anonymous
LOL! WAIT!
anonymous
  • anonymous
I got the mistake >_< sorry!
anonymous
  • anonymous
it's supposed to be : \[\frac{(m+6)(m+7) + (2m-1)(m-1)}{(m-2)(m-1)(m+7)}\]
anonymous
  • anonymous
so :
anonymous
  • anonymous
\[= \frac{m^2+13m+42+2m^2-3m+1}{(m-1)(m-2)(m+7)}\]\[= \frac{3m^2+10m+43}{(m-1)(m-2)(m+7)}\]
anonymous
  • anonymous
hmm, I'm not sure if we can simplify any further, correct me if I;m wrong please :)
anonymous
  • anonymous
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anonymous
  • anonymous
lol, yeah I got the question, but I'm not sure of my answer :)
anonymous
  • anonymous
I am sure of my steps though :)
anonymous
  • anonymous
=) nthank you no your fine im very confuse about this but i trust your answer
anonymous
  • anonymous
thank youuu soooo much!!!
anonymous
  • anonymous
all I did was factor and get them to have the same denominator, and you're welcome ^_^
anonymous
  • anonymous
=) but why did you do those steps
anonymous
  • anonymous
or how? so i can do them for more problems

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