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anonymous

  • 5 years ago

Hi do anyone know how to do Rational Expressions. m+6/m^2-3m+2m-1/m^2+5m-14

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  1. anonymous
    • 5 years ago
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    is it :\[\frac{m+6}{m^2-3m} + \frac{2m-1}{m^2+5m-14}?\]

  2. anonymous
    • 5 years ago
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    m+6m2−3m+2 +2m−1m2+5m−14 there's two (2)s but that setup is right

  3. anonymous
    • 5 years ago
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    no fractions? lol I'm confused now

  4. anonymous
    • 5 years ago
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    lol yes fractions i just dont know how to put it on. its my first time on this. your set up is right. but you were missing a number 2 on m^2-3m+2 =)

  5. anonymous
    • 5 years ago
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    try to put brackets for those with fractions :)

  6. anonymous
    • 5 years ago
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    oh, so my equation was right? all I have to do is add a 2?

  7. anonymous
    • 5 years ago
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    yes

  8. anonymous
    • 5 years ago
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    okay :)

  9. anonymous
    • 5 years ago
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    =) your soo awesome for helping me double =D

  10. anonymous
    • 5 years ago
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    lol ^_^

  11. anonymous
    • 5 years ago
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    thank you )

  12. anonymous
    • 5 years ago
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    lol

  13. anonymous
    • 5 years ago
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    alright, so after factoring the denominators we'll get:\[\frac{m+6}{(m-1)(m-2)} + \frac{2m-1}{(m+2)(m-7)}\] now get them to have the same denominators: \[\frac{(m+6)(m+2)(m-7) + (2m-1)(m-1)(m-2)}{(m+2)(m-2)(m-1)(m-7)}\]

  14. anonymous
    • 5 years ago
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    hmmm, there's something wrong

  15. anonymous
    • 5 years ago
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    are you sure of your question?

  16. anonymous
    • 5 years ago
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    LOL! WAIT!

  17. anonymous
    • 5 years ago
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    I got the mistake >_< sorry!

  18. anonymous
    • 5 years ago
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    it's supposed to be : \[\frac{(m+6)(m+7) + (2m-1)(m-1)}{(m-2)(m-1)(m+7)}\]

  19. anonymous
    • 5 years ago
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    so :

  20. anonymous
    • 5 years ago
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    \[= \frac{m^2+13m+42+2m^2-3m+1}{(m-1)(m-2)(m+7)}\]\[= \frac{3m^2+10m+43}{(m-1)(m-2)(m+7)}\]

  21. anonymous
    • 5 years ago
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    hmm, I'm not sure if we can simplify any further, correct me if I;m wrong please :)

  22. anonymous
    • 5 years ago
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  23. anonymous
    • 5 years ago
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    lol, yeah I got the question, but I'm not sure of my answer :)

  24. anonymous
    • 5 years ago
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    I am sure of my steps though :)

  25. anonymous
    • 5 years ago
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    =) nthank you no your fine im very confuse about this but i trust your answer

  26. anonymous
    • 5 years ago
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    thank youuu soooo much!!!

  27. anonymous
    • 5 years ago
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    all I did was factor and get them to have the same denominator, and you're welcome ^_^

  28. anonymous
    • 5 years ago
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    =) but why did you do those steps

  29. anonymous
    • 5 years ago
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    or how? so i can do them for more problems

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