toxicsugar22
  • toxicsugar22
The number of websites is growing by 15% percent each month. In June 2005, there were 4000 websites. Write a formula for the number of websites as a fuction of months since june 2005. And hOW LONG WILL IT TAKE FOR THE NUMBER OF SITES TO reach 8000 and 16000?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
15*12*...maybe something like this
anonymous
  • anonymous
lol thinker, still here? :)
anonymous
  • anonymous
going going lol

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
scoot =P
anonymous
  • anonymous
Let y be the number of websites, and x the number of months. A relationship that represents them is given by: y=4000+0.15x.
anonymous
  • anonymous
\[y=4000+0.15x \rightarrow (*)\]
anonymous
  • anonymous
To find how long it will take to reach a certain number of websites, just plug that number in y, and then solve for x.
anonymous
  • anonymous
you mean solve for y, right anwar?
anonymous
  • anonymous
No. I mean solve for x, since x represents the months and y represents the number of websites.
anonymous
  • anonymous
but she wants the number of websites and not months
anonymous
  • anonymous
wait, nvm lol, I misread the question >_<
anonymous
  • anonymous
my bad ^_^
anonymous
  • anonymous
Let's take the first one, reaching 8000.
toxicsugar22
  • toxicsugar22
wait can you tell me the formula aginain with T being the input variable
anonymous
  • anonymous
Just put T instead of x.
toxicsugar22
  • toxicsugar22
ok
toxicsugar22
  • toxicsugar22
so now will you help me with pluging the nubers in
anonymous
  • anonymous
So, let's do the part when it reaches 8000 websites. Substitute in (1) by "y=8000": \[y=4000+0.15x \implies 8000=4000+0.15x \rightarrow(1)\] Solving equation (1), by first subtracting 4000 from both sides and then dividing by 0.15
anonymous
  • anonymous
OMG.. I got a large number that does not seem right to me.
anonymous
  • anonymous
Just let me check my steps.
anonymous
  • anonymous
Oh I did a big mistake. My first step wasn't right. The problem is much more complicated.
anonymous
  • anonymous
Ok. Focus now. let y be the number of websites, and T the number of months, the relation is given by: \[y={0.15y \over x}+4000 \rightarrow(1)\]
anonymous
  • anonymous
I meant: \[y={0.15y \over T}+4000\]
toxicsugar22
  • toxicsugar22
tha is the formula
anonymous
  • anonymous
Yeah!! the first one was wrong.
anonymous
  • anonymous
Sorry about that.
anonymous
  • anonymous
you can simplify it more, or just leave it as it is.
anonymous
  • anonymous
Now plug y=8000, and solve for x: \[8000={0.15(8000) \over x}+4000 \implies 8000x=1200+4000x \implies 4000x=1200\] \[\implies x={1200 \over 4000} \implies x=0.3\] That means it would take 0.3 months (9 days) to reach to 8000 websites.
anonymous
  • anonymous
Similarly, You can do it for 16000.
toxicsugar22
  • toxicsugar22
OK I GOT IT
anonymous
  • anonymous
Good!! I hope it makes sense to you :)
anonymous
  • anonymous
if it is increasing by 15%per month then how can it double in just 9 days
anonymous
  • anonymous
^^ point :(
toxicsugar22
  • toxicsugar22
OK CAN YOU HELP ME WITH ANOTHER pROMBLEM . ACTUALLY it was solved earlier by someone else but They got it wrong I want to see if you will guide me the right way
anonymous
  • anonymous
ok i will try but it may take few minutes
anonymous
  • anonymous
TW= I(1 + r/q)nq TW-total web I-initial web q-number of months n-number of years
anonymous
  • anonymous
r-rate
toxicsugar22
  • toxicsugar22
At a concert By the Who in 1976, the sound level 50 meters from the stag registered 120 decibles. The treshold of pain for the human ear is 90 decibles. Calculate the sound intensity of the Who concert and the sound intenisity of the treshold of pain.
toxicsugar22
  • toxicsugar22
can u help me with this qetion please jas
anonymous
  • anonymous
i m sorry i m not sure about it

Looking for something else?

Not the answer you are looking for? Search for more explanations.