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anonymous
 5 years ago
Will someone please verify if my answers are correct for the following 2 problems.
Use Polynomial division to find the quotient Q(x) and the remainder R(x) when the first polynomial is divided by the second polynomial.
#1) x^51, x^21
My answers are Q(x) = x^3+x, R(x)= x1
#2) x^481, x+3
My answers are Q(x) = x^3, R(x) = 0
Thanks
anonymous
 5 years ago
Will someone please verify if my answers are correct for the following 2 problems. Use Polynomial division to find the quotient Q(x) and the remainder R(x) when the first polynomial is divided by the second polynomial. #1) x^51, x^21 My answers are Q(x) = x^3+x, R(x)= x1 #2) x^481, x+3 My answers are Q(x) = x^3, R(x) = 0 Thanks

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amistre64
 5 years ago
Best ResponseYou've already chosen the best response.0x^3 +x < Q(x)  x^21 x^5 1 x^5 +x^3  x^3 1 x^3 +x  x1 < remainder

radar
 5 years ago
Best ResponseYou've already chosen the best response.0From inspection, it looks like you got the #2 wrong also. Take your answer and multiply it by the divisior x^3(x+3)=x^4+3x^3 this does not equal x^481 !!.. So I would say back to the drawing board.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hi Jany, Still struggling with division of polynomials !!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Well done Jany, the first one is ABSOLUTELY CORRECT !!!!

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0BUT in the second one u made some basic mistakes........

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So I'll tell you a foolproof method. See in your second questiuon you have highest power of x as 4 but other powers are missing So before you start division you put all the missing powers with zero coefficient So \[x ^{4}81\] becomes \[x ^{4}+0x ^{3}+0x ^{2}+0x81\] So, now you have x with decreasing powers upto 1 and since the coeeficients of the terms you have put in are zeros, they are all zeros and hence do not affect the polynomial

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now we divide as follows : x^3  3x^2 + 9x 27  x+3  x^4 + 0x^3 + 0x^2 + 0x 81 x^4  3x^3   3x^3 + 0x^2 + 0x  81 + 3x^3 + 9x^2  + 9 x^2 + 0x  81  9x^2  27x   27x  81 + 27x + 81  0  So Q(x) = x^3  3x^2 + 9x  27 and R(x) = 0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0See how simple it becomes. Pls note that while writing the products I hv changed the signs as required (as I had explained to you over SKYPE) I'll be online later in the day. So, if you want i can explain it over SKYPE.
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