anonymous
  • anonymous
(2b-3)(3b-8)=0 am i correct with the answer of -6 and 8 for being the solution to this?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Try substituting in the solutions: (2(-6) -3)(3(-6) - 8) = 0 (-12-3)(-18-8)=0 (-15)(-26)=0 So they are not the solutions.
anonymous
  • anonymous
Instead set each factor equal to 0 and solve: 2b-3 = 0 and 3b-8 = 0
anonymous
  • anonymous
i dotn get what the solutions would be somehow i keep coming up with -6 and 8

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
2b - 3 = 0 add 3 to both sides 2b = 3 now divide by 2 b = 3/2
anonymous
  • anonymous
I think you were multiplying on the last step instead of dividing by mistake.
anonymous
  • anonymous
so 3/2 is one solution so what would the second solution be
anonymous
  • anonymous
b = 3/2 , b= 8/3
anonymous
  • anonymous
Try to solve the other equation we had earlier: 3b - 8 = 0
anonymous
  • anonymous
ok
anonymous
  • anonymous
3z^2+12z=0 one solution would be 0 is that the only solution
anonymous
  • anonymous
yeah

Looking for something else?

Not the answer you are looking for? Search for more explanations.