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anonymous

  • 5 years ago

(2b-3)(3b-8)=0 am i correct with the answer of -6 and 8 for being the solution to this?

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  1. anonymous
    • 5 years ago
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    Try substituting in the solutions: (2(-6) -3)(3(-6) - 8) = 0 (-12-3)(-18-8)=0 (-15)(-26)=0 So they are not the solutions.

  2. anonymous
    • 5 years ago
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    Instead set each factor equal to 0 and solve: 2b-3 = 0 and 3b-8 = 0

  3. anonymous
    • 5 years ago
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    i dotn get what the solutions would be somehow i keep coming up with -6 and 8

  4. anonymous
    • 5 years ago
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    2b - 3 = 0 add 3 to both sides 2b = 3 now divide by 2 b = 3/2

  5. anonymous
    • 5 years ago
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    I think you were multiplying on the last step instead of dividing by mistake.

  6. anonymous
    • 5 years ago
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    so 3/2 is one solution so what would the second solution be

  7. anonymous
    • 5 years ago
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    b = 3/2 , b= 8/3

  8. anonymous
    • 5 years ago
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    Try to solve the other equation we had earlier: 3b - 8 = 0

  9. anonymous
    • 5 years ago
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    ok

  10. anonymous
    • 5 years ago
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    3z^2+12z=0 one solution would be 0 is that the only solution

  11. anonymous
    • 5 years ago
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    yeah

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