anonymous
  • anonymous
someone please help with this algebra!
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
i have to solve for x 8/(x^2-1) + 4x/(x-1) + 8/(x+1) = 0
dumbcow
  • dumbcow
combine fractions by finding common denominator can you factor x^2 -1 ?
anonymous
  • anonymous
(x+1)(x-1)

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dumbcow
  • dumbcow
good and the other 2 denominators are factors of that right
anonymous
  • anonymous
yeah but i get lsot after that
dumbcow
  • dumbcow
ok so our denominator will be (x+1)(x-1) for the 1st fraction nothing changed, 2nd fraction we added (x+1) so add (x+1) to numerator, 3rd fraction we added (x-1) so add (x-1) to numerator
anonymous
  • anonymous
so 8 +4x(x+1)+8(x-1)=0
dumbcow
  • dumbcow
yes but that is all over (x-1)(x+1)
anonymous
  • anonymous
ohhh i forgot that step
anonymous
  • anonymous
8+4x+8=0
anonymous
  • anonymous
4x=16 so therefore x=4??
dumbcow
  • dumbcow
now here is shortcut, because it equals 0 the denominator doesnt matter 0/x = 0 so set numerator equal to 0 and solve for x
anonymous
  • anonymous
did u get 4?
dumbcow
  • dumbcow
you cant cancel the (x+1) and (x-1) because there is addition on numerator
anonymous
  • anonymous
i have 4x^2 +12x=0
anonymous
  • anonymous
and now im lost again
dumbcow
  • dumbcow
good so far try factoring out an x
dumbcow
  • dumbcow
i mean take an x away from each term then you will have a product =0 solve for each part setting it equal to 0 you will have 2 answers

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