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there is a formula for this. do you know it / did you use it for the first question?

yes
it is A=P(1+r/n)^nt

ok so:
r = .10
n = 365
A = 3*P
\[3*P = P*(1+\frac{.1}{365})^{.1*t}\]solve for t.

so what do we do know

do i divide by 3

so 3=p(1+10/365)^365/t

is it right

no. after dividing by P:\[3= (1+\frac{.1}{365})^{.1*t}\]

ok
can you help me do that
it really hard for me

please

ok can u help more

what do you not understand?

the log

its so complicated

can you use a calculator?

maybe if you go step by step with me then i will get it

yes i can use a calc.

i can but i still need help

take the log(3), then divide by the other log. then divide by .1

ok log 3 is .47712125

now i divide by what

log(1+.1/365)

i got 1.18968

is it right

is it right

i got .4010500723

ok But isnt it .10 instead of .1

those are the same number! .1 = .10 = .100 = .10000000

so what is the answere

can you not calculate it? it would be better then me just giving it to you.

i tried

ut i got a weird answer and im not sure i got it right

it 40104.8

is that it

that doesn't seem right though, heh. does it?

no it doesnt

because i messed up! it is n*t, not r*t.
so you should not divide by .1, but by 365

ok

so now can u help again

yes

You do it also and then we will compare aur answers

okay

i just did it. click on that link. it is an online calculator.

ok i got 10991.6

is that what you got

ok thanks

im going to give you a medal and be your fan if you be my fan

do u agree

u there