Can someone please explain to me how to find an equation of the line containing the given points (1/6,-1/3) and (5/6,3)

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Can someone please explain to me how to find an equation of the line containing the given points (1/6,-1/3) and (5/6,3)

Mathematics
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yes :)
1) find out the "slope" between the points by subtracting one from the other
x,y (5/6 , 3 ) - (1/6, -1/3) ------------- (4/6,8/3) slope = y/x = (8/3)/(4/6) and that can be simplified

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:D y-y1=m(x1-x)
8/3 8 6 --- = -- * -- = 2*2 = 4 4/6 4 3 slope is = 4
the equation of a line is y = "slope" * x + b; and it needs to contain at least one of the points given :) perferably both; but we have the slope, so we only need one of them to work it out
y = mx + b; (x=5/6, y=3) 3 = (4)(5/6) + b ; solve for b 3 = 20/6 +b 3 - 10/3 = b -1/3 = b the equation of the line is: y = 2x - 1/3 which can be written also as... 2x -y = 1/3
.... arg!! typoed it lol
y = 4x - (1/3) -4x +y = -1/3 4x -y = 1/3 are all equal equations for this line

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