anonymous
  • anonymous
(8^-6+7^-8)^0*5*2^-1+2*4^-1*2*3^-2+3*9^-1*(4^-1+3^-2)^0
Mathematics
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
= [1 x 5 x (1/2)] +[(1/9)] + [ (1/3) ]
anonymous
  • anonymous
53/18
anonymous
  • anonymous
huh?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
dont question the genius ><
anonymous
  • anonymous
I shall never, however, I'm totally LOST lol
anonymous
  • anonymous
Thats the answer to this equation?
anonymous
  • anonymous
is not an equation to start with, its an expression
anonymous
  • anonymous
anything to the power of zero is 1 a^0 =1 and a^-n = 1/a^n
anonymous
  • anonymous
know them and the question is easy
anonymous
  • anonymous
and remember bodmas, multiplaction done before addition
anonymous
  • anonymous
understood, thanks... :( sorry
anonymous
  • anonymous
for example , the first term (8^-6+7^-8)^0 looks complicated , but its just 1 , because anything to the power zero is 1
anonymous
  • anonymous
except zero to the power zero which is undefined
anonymous
  • anonymous
right
anonymous
  • anonymous
So those were fractions in the answer right?

Looking for something else?

Not the answer you are looking for? Search for more explanations.