the equation of the line tangent to the curve y=kx+8/k+x at x= -2 is y=x+4. what is the value of k?

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

the equation of the line tangent to the curve y=kx+8/k+x at x= -2 is y=x+4. what is the value of k?

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

check your question , possibly a typo
no, thats it word for word
y= (k+1)x +(8/k) ( eqn of the "curve" , even though its a line )

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

the only way to have a tangent to a line , is for the tangent to be the line
so (k+1)x +(8/k) = x+4
now we are told they are a tangent at x=-2, so we could sub x=-2 into the above to find k , but we could also sub any value of x we like , these lines have to be the same for all x
but ill just sub x=-2 -2(k+1) + 8/k = 2 -2k(k+1) +8 = 2k -2k^2 -2k -2k +8 =0 -2k^2 -4k+8 =0 -2(k^2 +2k -4) =0
k^2 +2k -4 =0
how did you get that function?
(k+1)^2 = 5 k +1 = +-sqrt(5) k = -1+-sqrt(5)
not an answer
well your teacher is stupid
i doubt that you dont even know what the equation of the line tangent is
this is a question from an ap test so there are no typos
lol was the curve \[y=kx + \frac{8}{k+x}\] y =
if it was................ :|
use brackets when you are writting fractions on the net :|
put the kx on top also
sorry? didnt know
lol
y=(kx+8)/k+x
With the given info, one finds the tangent vector of the curve to be <1, -1> and the point of tangency to be (-2, 2). You can find k by plugging in (-2, 2).

Not the answer you are looking for?

Search for more explanations.

Ask your own question