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anonymous
 5 years ago
the equation of the line tangent to the curve y=kx+8/k+x at x= 2 is y=x+4. what is the value of k?
anonymous
 5 years ago
the equation of the line tangent to the curve y=kx+8/k+x at x= 2 is y=x+4. what is the value of k?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0check your question , possibly a typo

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no, thats it word for word

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0y= (k+1)x +(8/k) ( eqn of the "curve" , even though its a line )

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0the only way to have a tangent to a line , is for the tangent to be the line

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0so (k+1)x +(8/k) = x+4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now we are told they are a tangent at x=2, so we could sub x=2 into the above to find k , but we could also sub any value of x we like , these lines have to be the same for all x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0but ill just sub x=2 2(k+1) + 8/k = 2 2k(k+1) +8 = 2k 2k^2 2k 2k +8 =0 2k^2 4k+8 =0 2(k^2 +2k 4) =0

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0how did you get that function?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0(k+1)^2 = 5 k +1 = +sqrt(5) k = 1+sqrt(5)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0well your teacher is stupid

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i doubt that you dont even know what the equation of the line tangent is

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is a question from an ap test so there are no typos

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0lol was the curve \[y=kx + \frac{8}{k+x}\] y =

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if it was................ :

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use brackets when you are writting fractions on the net :

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0put the kx on top also

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0With the given info, one finds the tangent vector of the curve to be <1, 1> and the point of tangency to be (2, 2). You can find k by plugging in (2, 2).
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