anonymous
  • anonymous
the equation of the tangent line to the curve y=x^3-6x^2 at its point of inflection is? steps please
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
Find inflection points. First derivative set to zero, solve for x gives critical points. Find second derivative. Investigate 2nd derivative at critical points from negative infinity to positive infinity. It is quite a lot of steps, let me know when you get this far. I would give further instruction. Eventually the equation is y=32

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