if 0 < k

Mathematics
- anonymous

if 0 < k

Mathematics
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- anonymous

use equation option

- anonymous

\[\int\limits_{0}^{k} \cos(2x) dx =1/2\]
thats what i meant

- anonymous

[sin(2k)/2]-sin(0/2)=sin(2k)/2=1/2
sin(2k)=1
2k=[\pi/2\]
so k=\[\pi/4\]

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## More answers

- anonymous

why do you divide by 2?

- anonymous

as you have 2x

- anonymous

in more detail
put 2x=t..........(1)
now differentiate both sides
2dx=dt
dx=dt/2
and limits will change like this
t=0 at x=0 .......from (1)
t=2k

- anonymous

now solve interms of t

- anonymous

t is a random variable or what does it stand for?

- anonymous

random

- anonymous

sorry i dont get it still, i guess cause thats not how they have taught us over here...um are you showing me the antiderivative?

- anonymous

what's ur country name?

- anonymous

United States of America

- anonymous

k i was showing u the antiderivative

- anonymous

ohh ok.. i was told to add one to the power and divide by the new power, is that what you did?

- anonymous

it in the case of polynomial
i mean sometjing like....x^2 or x^100

- anonymous

um ok?

- anonymous

if you have sin (polynomial of degreee 1) or cos(polynomial of degree 1)
then simply do integretion 4 sin(x) or cos(x)
then divide it by integretion of polynomial

- anonymous

thats why you divided by 2 since it was in the polynomial?

- anonymous

sorry its late and im a sort of slow now

- anonymous

ok add me as fan

- anonymous

lol

- anonymous

your last name is patel?

- anonymous

a friend of mine in calculus is last named patel he is from india, in any way related? i know big world but we found a cousin of his in a math competition lol

- anonymous

no i don't know him but i m also from INDIA

- anonymous

i guess its a popular last name from over there

- anonymous

yep

- anonymous

what's ur full name

- anonymous

mine?

- anonymous

yeah!

- anonymous

benjamin vasquez

- anonymous

got it
any more q benjamin

- anonymous

nope! thank you so much

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