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anonymous
 5 years ago
if 0 < k <pi, then 0 (integral) k cos(2x) dx = 1/2 when k=?
anonymous
 5 years ago
if 0 < k <pi, then 0 (integral) k cos(2x) dx = 1/2 when k=?

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{0}^{k} \cos(2x) dx =1/2\] thats what i meant

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0[sin(2k)/2]sin(0/2)=sin(2k)/2=1/2 sin(2k)=1 2k=[\pi/2\] so k=\[\pi/4\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0why do you divide by 2?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0in more detail put 2x=t..........(1) now differentiate both sides 2dx=dt dx=dt/2 and limits will change like this t=0 at x=0 .......from (1) t=2k

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now solve interms of t

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0t is a random variable or what does it stand for?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry i dont get it still, i guess cause thats not how they have taught us over here...um are you showing me the antiderivative?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what's ur country name?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0United States of America

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0k i was showing u the antiderivative

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0ohh ok.. i was told to add one to the power and divide by the new power, is that what you did?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it in the case of polynomial i mean sometjing like....x^2 or x^100

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if you have sin (polynomial of degreee 1) or cos(polynomial of degree 1) then simply do integretion 4 sin(x) or cos(x) then divide it by integretion of polynomial

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thats why you divided by 2 since it was in the polynomial?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0sorry its late and im a sort of slow now

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0your last name is patel?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a friend of mine in calculus is last named patel he is from india, in any way related? i know big world but we found a cousin of his in a math competition lol

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0no i don't know him but i m also from INDIA

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i guess its a popular last name from over there

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0got it any more q benjamin

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0nope! thank you so much
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