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anonymous
 5 years ago
solve by completing the square.
anonymous
 5 years ago
solve by completing the square.

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0move all one side you get\[x^{2} +2x 24 =0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now you factour(x+6)(x4)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0this is quadratic equation form: [b±√(b^24(a)(c))]/(2(a)) a=2 b=4 c=3 [(4)±√((4)^2(4*2*(3))]/(2*2)) [(4)±√(16+24)]/(4) [(4)±2√(10)]/(4) x =1/2[±√(10)]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0The above method is not "completing the square"

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0annette the second you want do complete square?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Even in first one, it is splitting the middle term method and not completing the square

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thank you Harkirat for remind me let do again , can you do second one it late I have to go 2/2=1 , 1^2 =1 (x+1)^2=24+1 (x+1)^2=25 x +1 = √(25) x = 1± 5 x=6 or x= 4

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0For the second we proceed as follows: \[2x ^{2}4x3=0\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0First we take 3 to RHS as 3\[2x ^{2}4x=3\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Next we divide both sides by 2 (to get rid of the 2 in front of x^2) So we get \[x ^{2}2x=3/2\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now to complete the square we add 1^2 to both sides \[x ^{2}2x+1^{2}=3/2 + 1\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now left side is a complete square as follows \[(x1)^{2}= 5/2\] This gives \[x1 = \pm \sqrt{5/2}\] Now taking 1 to RHS we get the final answer \[x = 1 \pm \sqrt{5/2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0So the two roots/zeros of the given quadratic equation are \[1+\sqrt{5/2}\] and \[1\sqrt{5/2}\]
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