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anonymous
 5 years ago
Compute the integral of 1/(x*sqrt(x^325)) Hint: let u=x^(3/2)
anonymous
 5 years ago
Compute the integral of 1/(x*sqrt(x^325)) Hint: let u=x^(3/2)

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anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I don't know that your hint gets you there. Who gave the hint?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is on the review sheet

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i know the answer too if that helps. its 2/15 arcsec(x^(3/2)/5)+c

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In doing it, they manipulated in a way to use trig method.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah, you have to brush up on your trig method (some variation of tan^2=sec21). Using hint x under the square root turns to sq root of u^225 and you can do the trig method.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use this substitution

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I think he wants us to use the trig method. I just keep getting stuck. I have u=x^(3/2) du=3/2sqrt(x)dx 2/3du=sqrt(x)dx I would be able to solve from there but i dont have a sqrt(x)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use my method and multiply denominator and numerator by x^0.5 and put x^(3/2) as t^2+25

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0He's going to test us on the trig method...

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0oh...but even ur hint uses substitution

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0right, but isnt there a difference between trig substitution and regular substitution?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if u want to use trig then use sec^(2/3)t=x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0not really. Can you go through the process step by step?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0use (25*sec (t))^(4/3)=x so x^(3/2)=25*sec^2(t) so dx=25^(4/3)*(4/3)*sec^(1/3)(t)*sec(t)*tan(t)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0dx=c*sec^(4/3)(t)*tan(t) dt c=constant

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0now solve further i m very slow in typing

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Jas, give me a minute. I have the method his instructor is expecting.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OK, using hint \[u=x ^{3/2}\]Convert this all the way through you get \[u ^{2/3}=x\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if u will solve my expression then it will become simplified

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, but he is in school, he is learning a really helpful method, technique.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Just hold on one minute, let me finish, so the work don't get all muddled.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i have already told similar method before but he wants trig method

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0if u will use x^(3/2)25=t^2 then it will be more easier

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0New\[\int\limits_{?}^{?}[(2/3) du]/[(u ^{2/3}\sqrt{u ^{2}25}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0what happened to 2/3du=sqrt(x)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0it is 2/3du=sqrt(x)dx

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits_{?}^{?}[(2/3) du]/25\sec \theta \tan \theta\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I guess that should be derivative theta

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0i mean, what happens to the sqrt(x)?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0multiply deno and nume by x and cha... made mistake in calculation

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0In the substitution there is an extra \[\sqrt{5 \sec \theta}\] and that is = to sq rt of x. That is swallowed up in dtheta.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OK, I just noticed the square root of x is in bottom. How do I get it on top to be swallowed by dtheta, Jas?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0you solve complete expression in u first it will be 1/u*(......)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0One second, there is a fix for this, don't change it too much or uswag would get lost in translation.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0otherwise change directly which i already proposed earlier

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0OK, that is already wiped out uswag. when I bring sq rt x and dx on top, I have an extra sq rt x in bottom, they cancel each other out.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0there is no sqrt but there is x

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yes, but that x is converted to u^(2/3). In my conversion I keep u^2=5 sec theta and I wipe out sq root 5 theta or sq rt x.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Uswag, you seem to be following along. Does this make any sense?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0k...i was doing in other way

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Can we start the explanation from 2/3 du/ u^(2/3)(sqrt(u^225)..... i got lost in the explanation after that. so its 2/3 du= sqrt(x)dx so we have sqrt(x)dx on top.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thanks Jas, you been a great help.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0thanks 4 being my fan

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[{[2/(3\sqrt{x})]du}/[\sqrt{x}u ^{2}\sqrt{u ^{2}25}]\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[2/75\int\limits_{?}^{?}d \theta/\sec \theta \tan \theta\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Now you have a function you can integrate. Once you integrate you have to go back and change to x. These trig techniques are explained nicely in MIT lectures http://www.youtube.com/watch?v=CXKoCMVqM9s&feature=BFa&list=PL590CCC2BC5AF3BC1&index=25

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I'll write down some of the substitutions I made\[u^{2}25=5^{2}\sec ^{2}\theta5^{2}\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And that is equal to \[5^{2}\tan ^{2}\theta\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt{u ^{2}25}=\sqrt{5^{2}\sec ^{2}\theta5^{2}}=\sqrt{5^{2}\tan ^{2}\theta}=5\tan \theta\]

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0A lot of info, makes sense?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0yeah, after seeing the info plus that it does. Thanks!
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