At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

I don't know that your hint gets you there. Who gave the hint?

it is on the review sheet

i know the answer too if that helps. its 2/15 arcsec(x^(3/2)/5)+c

In doing it, they manipulated in a way to use trig method.

put (x^(3/2)-25)=t^2

use this substitution

use my method and multiply denominator and numerator by x^0.5
and put x^(3/2) as t^2+25

He's going to test us on the trig method...

who?

the teacher

oh...but even ur hint uses substitution

right, but isnt there a difference between trig substitution and regular substitution?

if u want to use trig then use sec^(2/3)t=x

got it?

not really. Can you go through the process step by step?

use (25*sec (t))^(4/3)=x
so x^(3/2)=25*sec^2(t)
so dx=25^(4/3)*(4/3)*sec^(1/3)(t)*sec(t)*tan(t)

dx=c*sec^(4/3)(t)*tan(t) dt
c=constant

now solve further i m very slow in typing

Jas, give me a minute. I have the method his instructor is expecting.

OK, using hint
\[u=x ^{3/2}\]Convert this all the way through you get \[u ^{2/3}=x\]

if u will solve my expression then it will become simplified

Yes, but he is in school, he is learning a really helpful method, technique.

Just hold on one minute, let me finish, so the work don't get all muddled.

i have already told similar method before but he wants trig method

k......go ahead

\[2/3 du =\sqrt{x}\]

if u will use x^(3/2)-25=t^2
then it will be more easier

New\[\int\limits_{?}^{?}[(2/3) du]/[(u ^{2/3}\sqrt{u ^{2}-25}\]

what happened to 2/3du=sqrt(x)?

it is 2/3du=sqrt(x)dx

\[\int\limits_{?}^{?}[(2/3) du]/25\sec \theta \tan \theta\]

I guess that should be derivative theta

i mean, what happens to the sqrt(x)?

multiply deno and nume by x
and cha... made mistake in calculation

you solve complete expression in u first
it will be 1/u*(......)

(.....)=u^2-25

now put u=sec(t)

otherwise change directly which i already proposed earlier

there is no sqrt but there is x

Uswag, you seem to be following along. Does this make any sense?

k...i was doing in other way

i need to go

Thanks Jas, you been a great help.

Thanks Jas

thanks 4 being my fan

\[{[2/(3\sqrt{x})]du}/[\sqrt{x}u ^{2}\sqrt{u ^{2}-25}]\]

\[2/75\int\limits_{?}^{?}d \theta/\sec \theta \tan \theta\]

I'll write down some of the substitutions I made\[u^{2}-25=5^{2}\sec ^{2}\theta-5^{2}\]

And that is equal to \[5^{2}\tan ^{2}\theta\]

\[u =5\sec \theta \]

\[\sqrt{u ^{2}-25}=\sqrt{5^{2}\sec ^{2}\theta-5^{2}}=\sqrt{5^{2}\tan ^{2}\theta}=5\tan \theta\]

A lot of info, makes sense?

yeah, after seeing the info plus that it does. Thanks!