. Which group does not belong: (My answer is )
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Well BMSK doesn't have a P, and all the other groups do.
REally....I totally missed this one. This was obvious...sorry for the trouble. I see it NOW!! Thank you.
No problem, its a distraction from my own maths work i need to do but can't find a proper proof.
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Where are you at. I'm in California. Found this site only today. It's a great resource.
Victoria, Australia. Same here, I googled my problem and an answer came up, but it was wrong :( the reasoning slightly dodgy.
What's yr question buckbelly??
A country wants to use 5 coin denominations to pay for all purchases from 1 to 29 in this currency. however only two coins are allowed in each transaction, whether one is given, two are given, or one is given and one is received doesn't matter. Show that at least six coins will be needed.
Sorry, this one is too much for me!!
I have a few answers but they don't work for proving it isn't, my best one goes like this but you can see the problem: if you give one coin: 5 possibilities, two coins, 15 possibilities (5+4+3+2+1), one given one received 10 (4+3+2+1). which gives 30 possibilities, but then it theoretically works.... :/ My closest would be something about they will end up having multiple of the same number.