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anonymous

  • 5 years ago

I am studying Diophantine equations, and I don't understand the underlined portion of my attachment. (Attached in my next post)

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  1. anonymous
    • 5 years ago
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    Here is my attachment. Please help.

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  2. anonymous
    • 5 years ago
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    change q back into b/d and see what happens?

  3. anonymous
    • 5 years ago
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    Hello.

  4. anonymous
    • 5 years ago
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    Hello, did you decide to abandon me? :)

  5. anonymous
    • 5 years ago
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    ??

  6. anonymous
    • 5 years ago
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    Remember you promised to look into those problems in this weekend

  7. anonymous
    • 5 years ago
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    Oh - I have been preoccupied. I'll look tomorrow. I can help you with this one now, though.

  8. anonymous
    • 5 years ago
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    I thought I did something wrong, perhaps said something I shouldn't have said, or something of that sort.

  9. anonymous
    • 5 years ago
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    No, you need to calm down :) I keep saying that.

  10. anonymous
    • 5 years ago
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    Do you want the answer to this one? ;)

  11. anonymous
    • 5 years ago
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    Or have you figured it out already?

  12. anonymous
    • 5 years ago
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    Yes ofcourse,

  13. anonymous
    • 5 years ago
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    Is that a thing to ask? :)

  14. anonymous
    • 5 years ago
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    No I haven't figured out anything

  15. anonymous
    • 5 years ago
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    Okay...look at the equation you get,\[p(x-x_0)+q(y-y_0)=0\]then\[(y-y_0)=-\frac{p(x-x_0)}{q}\]The left-hand side is an integer, and you're told that p and q are relatively prime, so for the right-hand side to remain an integer, it must be that q divides (x-x_0).

  16. anonymous
    • 5 years ago
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    What an idiot I am

  17. anonymous
    • 5 years ago
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    a(x-x0)+b(y-y0)=0 b(x-x0) = -a(y-y0) b/d=q; a/d=p q(y-y0) = -p(x-x0) (y-y0) = -p (x-x0)/q y-y0 =

  18. anonymous
    • 5 years ago
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    Thinking over this for the last 1 hour but didn't figure this thing out

  19. anonymous
    • 5 years ago
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    Just keep thinking of NUMBERS. These equations are about NUMBERS.

  20. anonymous
    • 5 years ago
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    Yeah, I understand it now. Infact as I told, I should have figured this thing myself. But couldn't

  21. anonymous
    • 5 years ago
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    I mean it is simple enough

  22. anonymous
    • 5 years ago
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    And I shouldn't have asked it

  23. anonymous
    • 5 years ago
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    Anyhow thanks thanks thanks thanks both of you

  24. anonymous
    • 5 years ago
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    yw

  25. anonymous
    • 5 years ago
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    np :)

  26. anonymous
    • 5 years ago
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    Anyhow - I need sleep.

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