A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 5 years ago
I am studying Diophantine equations, and I don't understand the underlined portion of my attachment. (Attached in my next post)
anonymous
 5 years ago
I am studying Diophantine equations, and I don't understand the underlined portion of my attachment. (Attached in my next post)

This Question is Closed

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Here is my attachment. Please help.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0change q back into b/d and see what happens?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Hello, did you decide to abandon me? :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Remember you promised to look into those problems in this weekend

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Oh  I have been preoccupied. I'll look tomorrow. I can help you with this one now, though.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I thought I did something wrong, perhaps said something I shouldn't have said, or something of that sort.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No, you need to calm down :) I keep saying that.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Do you want the answer to this one? ;)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Or have you figured it out already?

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Is that a thing to ask? :)

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0No I haven't figured out anything

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Okay...look at the equation you get,\[p(xx_0)+q(yy_0)=0\]then\[(yy_0)=\frac{p(xx_0)}{q}\]The lefthand side is an integer, and you're told that p and q are relatively prime, so for the righthand side to remain an integer, it must be that q divides (xx_0).

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0a(xx0)+b(yy0)=0 b(xx0) = a(yy0) b/d=q; a/d=p q(yy0) = p(xx0) (yy0) = p (xx0)/q yy0 =

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Thinking over this for the last 1 hour but didn't figure this thing out

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Just keep thinking of NUMBERS. These equations are about NUMBERS.

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Yeah, I understand it now. Infact as I told, I should have figured this thing myself. But couldn't

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0I mean it is simple enough

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0And I shouldn't have asked it

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Anyhow thanks thanks thanks thanks both of you

anonymous
 5 years ago
Best ResponseYou've already chosen the best response.0Anyhow  I need sleep.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.